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2 years ago

Does the point (4 , 9) satisfy the equation y = x - 5?

Mathematics

1 answer:

stepladder [879]2 years ago

6 0

Answer:

(4, 9) does not satisfy the equation

Step-by-step explanation:

Given the linear equation, y = x - 5, and the point, (4, 9):

We can determine whether (4, 9) is a solution to y = x - 5 by substituting their values into the equation.

x = 4, and y = 9:

y = x - 5

9 = 4 - 5

9 = -1 (False statement)

As demonstrated in our calculations, it turns out that (4, 9) does not satisfy the equation. Therefore, (4, 9) is not a solution to y = x - 5.

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NEED HELP ASAP !!! Simplify: √16r O 47² O 473 87² O 8-3

Vlad1618 [11]

Answer:

4 r^3

Step-by-step explanation:

sqrt ( 16 r^6 ) = sqrt ( 4^2 * (r^3)^2 ) = 4 r^3

6 0

2 years ago

Find a ratio equivalent to 8/3. Then, use te ratios to write a proportion

Galina-37 [17]

A ratio that is equivalent to 8/3 is 16/6.

Because:- 8*2= 16
3*2=6

16/6 is equivalent to 8/3

Writing a proportion:-

8/3=16/6

8 0

3 years ago

Read 2 more answers

Solve using the unit rate problems find the constant speed 60 miles in 1.5 hours what is the answer.

kherson [118]

40 miles per hour. if you take 60 divided by 1.5(the speed over time) you get 40mph

7 0

3 years ago

WILL GIVE U BRAINLIEST ♡ Rationalize the denominator of fraction with numerator square root of -36 divided by (2-3i)+(3+2i)

Dmitriy789 [7]

Answer:

$- \frac{3}{13} + \frac{15i}{13}$

Step-by-step explanation:

$\frac{ \sqrt{ - 36} }{(2 - 3i) + (3 + 2i)}$

Set up equation

Step 1: Simplify

$\frac{6i}{5 - i}$

Step 2:Multiply by conjugate

$\frac{6i}{5 - i} \times \frac{5 + i}{5 + i}$

Step 3:Simplify

$\frac{30i + 6 {i}^{2} }{ {i}^{2} - 5 {}^{2} }$

We can reduce this and we must make the imaginary number and real number serpate equations.

$- \frac{6}{26} + \frac{30i}{26}$

Reduce each by 2

$- \frac{3}{13} + \frac{15i}{13}$

7 0

3 years ago

7. 12, 24, 4, 18, 12, 9 Using the data, create a histogram.

Mnenie [13.5K]

Answer:

import pandas as pd

vec = pd.Series([7.12,24,4,18,12,9])

vec.plot(kind = 'hist')

Step-by-step explanation:

You can use python for that.

By doing

import pandas as pd

vec = pd.Series([7.12,24,4,18,12,9])

vec.plot(kind = 'hist')

And this is the result you get

5 0

3 years ago