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yanalaym [24]
2 years ago
11

7. A perfect cube has a width of 2 cm. What is the cube's volume? Show your work!

Physics
1 answer:
Mariana [72]2 years ago
8 0

Answer:

8cm^3

Explanation:

length*width*height=volume

2*2*2=8

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When tightening a bolt, you push perpendicularly on a wrench with a force of 165 N at a distance of 0.140 m from the center of t
choli [55]

Answer:

Part a)

\tau = 23.1 Nm

Part b)

\tau = 17.05 Foot pound force

Explanation:

As we know that torque is defined as the product of force and its perpendicular distance from reference point

so here we have

\tau = \vec r \times \vec F

now we have

\tau = (0.140)(165)

\tau = 23.1 Nm

Part b)

Now we know the conversion as

1 meter = 3.28 foot

1 N = 0.225 Lb force

now we have

\tau = 23.1 Nm

\tau = 23.1 (0.225 Lb)(3.28 foot)

\tau = 17.05 Foot pound force

3 0
3 years ago
11. Reflecting telescopes are popular because they're _______ than a refracting telescope.
Anon25 [30]
I do not know what the school expects as an answer, but advantage of reflecting telescopes is that there is only one major reflecting surface, so it is quite easy to create a 6 or 8 inch telescope by an amateur, after adding on a prism and an eyepiece.  (a microscope eyepiece could be used).
MY answer would be "easier to build".  (it still takes tens of hours to grind and polish the single plane surface to a parabolic surface).

Electromagnetic waves all have the same velocity in the same medium.  However, since frequencies vary widely, so do wavelengths.

4 0
3 years ago
Read 2 more answers
Suppose that you hear a clap of thunder 16 s after seeing the associated lightning strike. How far are you from the lightning st
riadik2000 [5.3K]

Answer:

d=5.376km

Explanation:

Since <em>light is so fast</em> we can assume no time passes between the lightning strikes and we observe it. We want to know then how far away did the strike occur for the sound to take 16s to reach our ears. Since the definition of velocity tells us that v=d/t, we can write d=vt=(336m/s)(16s)=5376m=5.376km

4 0
3 years ago
Numerical Problems:
dangina [55]
  • Displacement=1200m
  • Time=4min=4(60)=240s

\boxed{\sf Velocity=\dfrac{Displacement}{Time}}

\\ \sf\longmapsto Velocity=\dfrac{1200}{240}

\\ \sf\longmapsto Velocity=5m/s

6 0
3 years ago
Everyone's favorite flying sport disk can be approximated as the combination of a thin outer hoop and a uniform disk, both of di
Umnica [9.8K]

Answer:

The length of the boomerang is 0.364 m

Explanation:

The moment of inertia is:

I=\frac{1}{2} m_{d} r^{2} +m_{h} r^{2}

Where

md = 0.05 kg

mh = 0.12 kg

r = d/2 = 0.273/2 = 0.1365 m

I=\frac{0.05*(0.1365)^{2} }{2} +(0.12)*(0.1365)^{2} =2.7x10^{-3} kgm^{2}

The length of the boomerang is:

L_{b} =\sqrt{\frac{12I}{m} } =\sqrt{\frac{12*2.7x10^{-3} }{0.245} } =0.364m

5 0
3 years ago
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