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jek_recluse [69]
3 years ago
12

A car traveling at 22 m/s comes to an abrupt halt in 0.1 second when it hits a tree. What is the deceleration in meters per seco

nd per second (i.e. m/s/s or m/s2)?
Physics
1 answer:
QveST [7]3 years ago
6 0

Answer:

220 m/s²

Explanation:

given,

initial speed of car= 22 m/s

final speed of car= 0 m/s

time taken by car to stop= 0.1 s

acceleration of car is equal to change in velocity per unit time

  a = \dfrac{\Delta v}{t}

  a = \dfrac{v_f-v_i}{t}

  a = \dfrac{0-22}{0.1}

         a = -220 m/s²

negative sign represent deceleration of the body

hence, deceleration of car is equal to a = 220 m/s²

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Answer:

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Explanation:

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A crane lifts a 400 N crate full of baked beans 15 m. How much work was done by the crane?
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Answer:

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10) Two students want to use a 12-meter long rope to create standing waves. They first measure the speed at which a single wave
zhannawk [14.2K]

Answer:

To create a second harmonic the rope must vibrate at the frequency of 3 Hz

Explanation:

First we find the fundamental frequency of the rope. The fundamental frequency is the frequency of the rope when it vibrates in only 1 loop. Therefore,

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v = speed of wave = 36 m/s

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f₁ = fundamental frequency

Therefore,

f₁ = (36 m/s)/2(12 m)

f₁ = 1.5 Hz

Now the frequency of nth harmonic is given in general, as:

fn = nf₁

where,

fn = frequency of nth harmonic

n = No. of Harmonic = 2

f₁ = fundamental frequency = 1.5 Hz

Therefore,

f₂ = (2)(1.5 Hz)

<u>f₂ = 3 Hz</u>

5 0
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Calculate the tangential speed of a yo-yo twirled at the end of a 4 meter long string at 2 revolutions per second.
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