Answer:
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The horizontal change between two points on a graph is called the 'run'.
The vertical change between two points is called the 'rise'.
1.96s and 1.86s. The time it takes to a spaceship hovering the surface of Venus to drop an object from a height of 17m is 1.96s, and the time it takes to the same spaceship hovering the surface of the Earth to drop and object from the same height is 1.86s.
In order to solve this problem, we are going to use the motion equation to calculate the time of flight of an object on Venus surface and the Earth. There is an equation of motion that relates the height as follow:

The initial velocity of the object before the dropping is 0, so we can reduce the equation to:

We know the height h of the spaceship hovering, and the gravity of Venus is
. Substituting this values in the equation
:

To calculate the time it takes to an object to reach the surface of Venus dropped by a spaceship hovering from a height of 17m, we have to clear t from the equation above, resulting:
Similarly, to calculate the time it takes to an object to reach the surface of the Earth dropped by a spaceship hovering from a height of 17m, and the gravity of the Earth
.

Answer:
The angle between the emergent blue and red light is 
Explanation:
We have according to Snell's law

Since medium from which light enter's is air thus 
Thus for blue incident light we have

Similarly using the same procedure for red light we have

Thus the absolute value of angle between the refracted blue and red light is

If the charged particle moves in the magnetic field or electric field, then it experiences magnetic force or electric force because of its magnetic or electric properties.
<h3>What is magnetic field?</h3>
The magnetic field is the region of space where a charged object experiences magnetic force when it is moving.
When a charged particle such as an electron or proton moves inside a conductor, magnetic lines of force rotate around the particle. This relative motion causes the magnetic field to generate.
Thus, If the charged particle moves in the magnetic field or electric field, then it experiences magnetic force or electric force because of its magnetic or electric properties.
Learn more about magnetic field.
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