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Ivenika [448]
2 years ago
7

24 is 0.2​% of what​ number?

Mathematics
2 answers:
Softa [21]2 years ago
4 0
Agreed I got it correct thAble
Mandarinka [93]2 years ago
3 0

Answer:

12,000

Step-by-step explanation:

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65 yards because of a2+b2=c2
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Find the slope of the line that passes through (-11, 75) and (27, -9).
Marrrta [24]

Answer:

\frac{y__2-y__1}{x__2-x__1}

y = -9 + 75 = 66

x = 27-(-11) = 27 + 11 = 38

slope = 66/28

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A jewelry maker has 24 jade beads and 30 teak beads. What the the greatest number of necklaces she can make? How many beads of e
Darya [45]
Find the GCF of 24 and 30

  24                30
1×24              1×30
2×12             2×15
3×8               3×10
4×6               5×6

The common factors are 1, 2, 3, and 6

That means we can make 6 necklaces, each necklace with 4 jade beads and 5 teak beads. 

8 0
3 years ago
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Find the value of x and y
velikii [3]

Answer:

2x + 20 = 3x-10

2x -3x = -20-10

-x = -30

x= 30

Checking part:

2x+20 = 2(30) +20 = 60+20 = 80

3x-10 = 3(30) - 10 = 90-10 = 80

Hence, the final answer is x = 30.

Step-by-step explanation:

6 0
3 years ago
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A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h
mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed  = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere  =\frac{2}{3}\pi r^3

Volume of a Cylinder =\pi r^2 h

Therefore:

The Volume of the Solid formed

=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Area of the Hemisphere =2\pi r^2

Curved Surface Area of the Cylinder =2\pi rh

Total Surface Area=

2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh

Cost of the Hemispherical Ends  = 2 X  Cost of the surface area of the sides.

Therefore total Cost, C

=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh

Recall: h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Therefore:

C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}

The minimum cost occurs at the point where the derivative equals zero.

C^{'}=\frac{-27840+32\pi r^3}{3r^2}

When \:C^{'}=0

-27840+32\pi r^3=0\\27840=32\pi r^3\\r^3=27840 \div 32\pi=276.9296\\r=\sqrt[3]{276.9296} =6.518

Recall:

h=\frac{4640}{\pi r^2}-\frac{4r}{3}\\h=\frac{4640}{\pi*6.518^2}-\frac{4*6.518}{3}\\h=26.074 feet

Therefore, the dimensions that will minimize the cost are:

Radius =6.518 feet

Height = 26.074 feet

5 0
2 years ago
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