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AnnZ [28]
2 years ago
14

If 7 - 1 is 6 then what would it be if you multiply it by 11700 and subtract by 5000?

Mathematics
1 answer:
steposvetlana [31]2 years ago
8 0

Answer: 65200

7 - 1 = 6 x 11700 = 70200 - 5000 = 65200

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Find the lateral area and total surface area of each of the following. GEOMETRY!!! HELP PLS
AlexFokin [52]

(a) The lateral surface area of the prism is 720 sq units and the total surface area is 752 sq units.

(b) The lateral surface area of the cone is 136π sq units and the total surface area is 200π sq units.

(c) The lateral surface area of the cylinder is 242π sq units and the total surface area is 484π sq units.

<h3>Lateral surface area of the prism</h3>

L.S.A = Ph

where;

  • P is perimeter of the base
  • h is height of the prism

h² = 17² - 8²

h² = 225

h = 15

L.S.A = (3 x 16) x 15 = 720 sq units

<h3>Total surface area of the prism</h3>

T.S.A = PH + 2B

T.S.A = 720 + 2(16) = 752 sq units

<h3>Lateral surface area of the cone</h3>

L.S.A = πrt

where;

  • t is the slant height = 17

r² = 17² - 15²

r² = 64

r = 8

L.S.A = π(8)(17) = 136π sq units

<h3>Total surface area of the cone</h3>

T.S.A = πrt + πr²

T.S.A = 136π sq units + π(8)²

T.S.A = 200π sq units

<h3> Lateral surface area of the cylinder</h3>

L.S.A = 2πrh

where;

  • r is the radius of the cylinder = 11
  • h is height of the cylinder = 11

L.S.A = 2π(11 x 11) = 242π sq units

<h3>Total surface area of the cylinder</h3>

T.S.A = 2πrh + 2πr² = 2πr(r + h)

T.S.A = 2π(11)(11 + 11)

T.S.A = 484π sq units.

Thus, the lateral surface area of the prism is 720 sq units and the total surface area is 752 sq units.

  • the lateral surface area of the cone is 136π sq units and the total surface area is 200π sq units.
  • the lateral surface area of the cylinder is 242π sq units and the total surface area is 484π sq units.

Learn more about surface area here: brainly.com/question/76387

#SPJ1

3 0
2 years ago
18) A company is planning to manufacture a new blender. After conducting extensive
zhenek [66]

Answer:

  R(x) = -0.05x^2 +80x

Step-by-step explanation:

Given the two points (x, p), the equation for the price associated with a given demand quantity can be written using the 2-point form:

  p = (p2 -p1)/(x2 -x1)(x -x1) +p1

  p = (40 -50)/(800 -600)(x -600) +50

  p = -0.05x +80 . . . . simplify

Then the revenue equation is ...

  R(x) = xp

  R(x) = -0.05x^2 +80x

7 0
3 years ago
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