Answer:
Mass of compound = 0.24 g and, mass of boron = 0.096 g percentage of boron in the compound = mass of boron / mass of compound * 100 = 0.096/0.24 * 100 = 40% mass of oxygen = 0.144 g again, mass of compound = 0.24 g percentage of oxygen in compound = mass of oxygen/mass of of compound * 100 = 0.144/0.24 * 100 = 60%
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Its a form of anaesthesia used by dentists
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The oxidation-reduction reaction from the reactions above is
ZnS(s) + 2O2(g) ------ ZnSO4(s)
<h3>What is redox reactions?</h3>
Oxidation-reduction or redox reaction is the type of chemical reaction in which oxidation states of substrate changes
So therefore, the oxidation-reduction reaction from the reactions above is
ZnS(s) + 2O2(g) ------ ZnSO4(s)
Learn more about oxidation-reduction reactions:
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Knowing that 1 mL = 1000 uL , you just multiply by 1000
Beryllium<span> (Be), </span>magnesium<span> (</span>Mg), calcium (Ca), strontium (Sr<span>), </span>barium<span>(Ba) and radium (Ra). Elements are grouped together because they share similar properties.
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