The average atomic mass in amu of element X is 58.42 amu
The average atomic mass is the sum of the mass number of each of the isotopes multiplied by their respective abundances.
So;
The average atomic mass of element X is;
(58 * 0.68) + (60 * 0.26) + (0.06 * 62)
= 39.44 + 15.26 + 3.72
= 58.42 amu
The average atomic mass in amu of X is 58.42 amu.
Learn more: brainly.com/question/13292428
Answer:
1a) .68 moles 1b)4.1E-23 molecules.
2a) .37 moles 2b) 2.27E-23 molecules
Explanation:
1a) CO2 is equal to 44 grams (C→12 grams,O→16 grams[·2]) .30g/44g is .68 moles.
1b) multiply 1A by advogadros number (6.022E-23)
2a) NaCl is 58 grams. 22/58 is .37 moles.
2b) multiply 2A by advogadros number.
you'd answer #3 the same way #1 and #2
Answer: experiments are use to test if an hypothesis is right or wrong
Explanation:
