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Goshia [24]
3 years ago
5

A force of 100 newtons is applied to a box at an angle of 36º with the horizontal. If the mass of the box is 25 kilograms, what

is the horizontal acceleration of the box? 1.52 meters/second2
Chemistry
1 answer:
notka56 [123]3 years ago
5 0

Answer:

a_x=4.944m/s^2

Explanation:

Hello,

Based on the acting force that is applied horizontally, one can propose the following equation based on Newton's laws:

F=ma

Nevertheless, since we've got a angled force, it becomes:

F=macos\theta

In this case, cos\theta accounts for the formed angle, so the horizontal acceleration turns out into:

a_x=\frac{F}{mcos\theta}=\frac{100kg*\frac{m}{s^2} }{25kgcos(36^0)}=4.944m/s^2

Best regads.

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Answer:

By the time the Vesuvius eruption sputtered to an end the next day, Pompeii was buried under millions of tons of volcanic ash. About 2,000 Pompeiians were dead, but the eruption killed as many as 16,000 people overall. By

the time the Vesuvius eruption sputtered to an end the next day, Pompeii was buried under millions of tons of volcanic ash. About 2,000 Pompeiians were dead, but the eruption killed as many as 16,000 people overall.

Explanation:

5 0
3 years ago
given the mass lost during the reaction when the alka seltzer is the limiting reagent and that the molar mass of carbon dioxide
Vadim26 [7]
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5 0
3 years ago
For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ
Komok [63]

Answer:

Check the explanation

Explanation:

Answer – Given, H_3PO_4 acid and there are three Ka values

K_{a1}=6.9x10^8, K_{a2} = 6.2X10^8, and K_{a3}=4.8X10^{13}

The transformation of H_2PO_4- (aq) to HPO_4^2-(aq)is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

Mass of KH2PO4 = 22.0 g , mass of Na2HPO4 = 32.0 g , volume = 1.00 L

First we need to calculate moles of each

Moles of KH2PO4 = 22.0 g / 136.08 g.mol-1

                             = 0.162 moles

Moles of Na2HPO4 = 32.0 g /141.96 g.mol-1

                             = 0.225 moles

[H2PO4-] = 0.162 moles / 1.00 L = 0.162 M

[HPO42-] = 0.225 moles / 1.00 L = 0.225 M

Now we need to calculate the pKa2

pKa2 = -log Ka

       = -log 6.2x10-8

       = 7.21

We know Henderson-Hasselbalch equation

pH = pKa + log [conjugate base] / [acid]

pH = 7.21 + log 0.225 / 0.162

     = 7.35

The pH of a buffer solution obtained by dissolving 22.0 g of KH2PO4 and 32.0 g of Na2HPO4 in water and then diluting to 1.00 L is 7.35

6 0
3 years ago
PLEASE HELP ME OUT!!
vesna_86 [32]

Answer:

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Explanation:

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Nezavi [6.7K]
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