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Goshia [24]
3 years ago
5

A force of 100 newtons is applied to a box at an angle of 36º with the horizontal. If the mass of the box is 25 kilograms, what

is the horizontal acceleration of the box? 1.52 meters/second2
Chemistry
1 answer:
notka56 [123]3 years ago
5 0

Answer:

a_x=4.944m/s^2

Explanation:

Hello,

Based on the acting force that is applied horizontally, one can propose the following equation based on Newton's laws:

F=ma

Nevertheless, since we've got a angled force, it becomes:

F=macos\theta

In this case, cos\theta accounts for the formed angle, so the horizontal acceleration turns out into:

a_x=\frac{F}{mcos\theta}=\frac{100kg*\frac{m}{s^2} }{25kgcos(36^0)}=4.944m/s^2

Best regads.

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We will see that the volume of the unit cell is 144,070,699.06 pm^3

<h3>How to get the volume of a body-centered cubic unit cell?</h3>

In a body-centered cubic unit cell, the side length of the cube is given as:

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And the volume of a cube is the side length cubed, then we can see that the volume of our cube will be:

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Solving that we get:

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