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2 years ago

determine if the pennies are made of pure copper by comparing the density with that of the pure copper

Chemistry

1 answer:

zhenek [66]2 years ago

4 0

Answer:

The pennies are NOT made of pure copper since the obtained density is 9.29 g/cm3 which is greater than the density of copper which is 8.96 g/cm3.

Explanation:

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For the mineral torbernite, Cu(UO2)2(PO4)2⋅8H2O, determine the total number of atoms in one formula unit

ASHA 777 [7]

Answer:

$2.47x10^{25}atoms$

Explanation:

Hello,

In this case, since the mineral torbernite has one copper atom, two uranium atoms, twenty oxygen atoms (2x2+4x2+8), two phosphorous atoms and sixteen hydrogen atoms (12x2) and therefore forty one in total, by using the Avogadro's number one is able to compute the total number of atoms in one formula unit or one mole:

$Atoms=1molCu(UO_2)_2(PO_4)_2\dot \ 8H_2O*\frac{41mol\ of \ atoms}{1molCu(UO_2)_2(PO_4)_2\dot \ 8H_2O}*\frac{6.022x10^{23}atoms}{1mol\ of \ atoms} \\\\=2.47x10^{25}atoms$

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2 years ago

What do the digestive system and skeletal system have in common?

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Answer:

Answer:Your skeletal system relies on the nutrients it gains from your digestive system to bulid strong healthy bones .A body system is a group of parts that work together to serve a common purpose .

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3 years ago

11. The strength of a force is measured in

dem82 [27]

Answer:

In units.

Explanation:

Such as newtons or pounds.

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3 years ago

Acids which contain only hydrogen and a single other element are referred to as.

Pachacha [2.7K]

$\huge{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red}Answer}}}}$

A binary acid is an acid that consists of hydrogen and one other element.

8 0

1 year ago

At 400 K oxalic acid decomposes according to the reaction:H2C2O4(g)→CO2(g)+HCOOH(g)In three separate experiments, the intial pre

padilas [110]

Answer:

v = 2,66x10⁻⁵ P[H₂C₂O₄]

Explanation:

For the reaction:

H₂C₂O₄(g) → CO₂(g) + HCOOH(g)

At t = 0, the initial pressure is just of H₂C₂O₄(g). At t= 20000 s, pressures will be:

H₂C₂O₄(g) = P₀ - x

CO₂(g) = x

HCOOH(g) = x

P at t=20000 is:

P₀ - x + x + x = P₀+x. That means P at t=20000s - P₀ = x

For 1st point:

x = 92,8-65,8 = 27

Pressure of H₂C₂O₄(g) at t=20000s: 65,8-27 = 38,8

2nd point:

x = 130-92,1 = 37,9

H₂C₂O₄(g): 92,1 - 37,9 = 54,2

3rd point:

x = 157-111 = 46

H₂C₂O₄(g): 111-46 = 65

Now, as the rate law is :

v = k P[H₂C₂O₄]

Based on integrated rate law, k is:

(- ln P[H₂C₂O₄] + ln P[H₂C₂O₄]₀) / t = k

1st point:

k = 2,64x10⁻⁵

2nd point:

k = 2,65x10⁻⁵

3rd point:

k = 2,68x10⁻⁵

The averrage of this values is:

k = 2,66x10⁻⁵

That means law is:

v = 2,66x10⁻⁵ P[H₂C₂O₄]

I hope it helps!

4 0

2 years ago