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Andreyy89
3 years ago
9

The atoms of Group B elements _____ electrons when they form ions. options: A.either gain or lose B.gain C.cannot be determined

D.lose
Chemistry
2 answers:
grigory [225]3 years ago
6 0

The answer to the question :

The atoms of Group B elements _____ electrons when they form ions .

is :

D) lose

The atoms of Group B elements lose electrons when they form ions because these elements are metals.

Harrizon [31]3 years ago
6 0
They tend to lose electrons to became positive ions( cation ) .
Hope it help :)
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An important industrial route to extremely pure acetic acid is the reaction of methanol with carbon monoxide:
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The reaction has had a heat that is enthalpy of -22 kJ/mol. The exothermic process has been signaled by the negative sign.

The amount of energy that the system absorbs or releases to create the products is described as the heat of reaction.

The source of the reaction's heat is

H is equal to 3(413 Kj/mol) + 358 Kj/mol + 467 Kj/mol + 1070 Kj/mol = 3134 Kj/mol.

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7 0
1 year ago
.What threatens the newly hatched chicks?
marysya [2.9K]

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6 0
3 years ago
Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of
bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol..[1]

O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol..[2]

NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol..[3]

NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}

2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol

2\times \Delta H^o_{4}=470.3 kJ/mol

\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0
3 years ago
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