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maw [93]
3 years ago
15

Question

Chemistry
1 answer:
Paul [167]3 years ago
8 0

Answer: A,B

Explanation:

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12.70 L of a gas has a pressure of 0.63 atm. What is the volume of the gas at 105kPa?
Zielflug [23.3K]

Answer: 7.693 L

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=0.63atm\\V_1=12.70L\\P_2=105kPa=1.04atm(1kPa=0.009atm)\\V_2=?

Putting values in above equation, we get:

0.63\times 12.70mL=1.04\times V_2\\\\V_2=7.693L

Thus new volume of the gas is 7.693 L

6 0
3 years ago
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As you move down through the family of alkali metals, the first ionization energy ________ because
kompoz [17]
I’m pretty sure the answer is B
5 0
2 years ago
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A sealed 10.0 L flask at 400 K contains equimolar amounts of ethane and propanol in gaseous form. Which of the following stateme
Phoenix [80]

Answer:

(C) The average molecular speed of ethane is equal to the average molecular speed of propanol.

Explanation:

When dealing with gases, you know that the temperature and speed are related. When held at a constant temperature, the speed is also held constant. We also know that ideal gases behave the same despite their identities.

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2 years ago
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Why carbon dioxide can be tested with the help of moist blue litmus paper ?<br>​
Evgesh-ka [11]

Answer:

carbon dioxide is acidic and when it comes in contact with blue litmus paper it turns red

Explanation:

4 0
3 years ago
The cell potential of a redox reaction occurring in an electrochemical cell under any set of temperature and concentration condi
avanturin [10]

Answer : The actual cell potential of the cell is 0.47 V

Explanation:

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given redox reaction is :

Ni^{2+}(aq)+Zn(s)\rightarrow Ni(s)+Zn^{2+}(aq)

The balanced two-half reactions will be,

Oxidation half reaction : Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction : Ni^{2+}+2e^-\rightarrow Ni

The expression for reaction quotient will be :

Q=\frac{[Zn^{2+}]}{[Ni^{2+}]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(0.0141)}{(0.00104)}=13.6

The value of the reaction quotient, Q, for the cell is, 13.6

Now we have to calculate the actual cell potential of the cell.

Using Nernst equation :

E_{cell}=E^o_{cell}-\frac{RT}{nF}\ln Q

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = 316 K

n = number of electrons in oxidation-reduction reaction = 2 mole

E^o_{cell} = standard electrode potential of the cell = 0.51 V

E_{cell} = actual cell potential of the cell = ?

Q = reaction quotient = 13.6

Now put all the given values in the above equation, we get:

E_{cell}=0.51-\frac{(8.314)\times (316)}{2\times 96500}\ln (13.6)

E_{cell}=0.47V

Therefore, the actual cell potential of the cell is 0.47 V

4 0
3 years ago
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