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Anarel [89]
3 years ago
6

One of the legs of a right triangle measures 13 cm and the other leg measures 1 cm. Find the measure of the hypotenuse. If neces

sary, round to the nearest tenth.
Mathematics
1 answer:
velikii [3]3 years ago
3 0

Answer:

hypotenuse = 13.0 cm

Step-by-step explanation:

Given the dimensions of a right triangle whose legs have measures of 13 cm and 1 cm, we can use the Pythagorean Theorem to find the measure of the triangle's hypotenuse.

The <u>Pythagorean Theorem</u> states that the squared measure of a right triangle's hypotenuse is equal to the sum of the squared lengths of its legs. In other words:

Pythagorean Theorem:   c² = a² + b²

Let c = hypotenuse

     a  =  Leg₁   = 1 cm

    b  =  Leg₂  =  13 cm

Substitute these values into the given formula to find the measure of the hypotenuse, c:

c² = a² + b²

c² = ( 1 )² + (13)²

c² = 1 + 169

c² = 170

Next, take the square root of c² and 170 to isolate c:

\displaystyle\mathsf{\sqrt{c^2}\:=\:\sqrt{170}}

c = 13.04 or 13.0 cm

Therefore, the length of the hypotenuse is 13.0 cm.

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KatRina [158]
You need to use the cross product method to find your answer :

1 pizza = 2 ½ cups
3 pizzas = × cups

((2 ½) • 3) ÷ 1 = × cups

7 ½ ÷ 1 = × cups

7 ½ = × cups

⇨ So your answer is: You would need to use 7 ½ cups of flour to make 3 handmade pizzas!

There you go. I really hope this helped, if there’s anything just let me know! ☻
3 0
3 years ago
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Sidana [21]
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4 0
3 years ago
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Vinvika [58]
D is the right answer

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Your welcome!
4 0
3 years ago
1. The difference of five times a number and 6 is -2.
OlgaM077 [116]

Answer:

13

Step-by-step explanation:

5-x+6=-2

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5 0
3 years ago
A skier has decided that on each trip down a slope, she will do 3 more jumps than before. On her first trip she did 5 jumps. Der
taurus [48]
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.

Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.

Let us try it below:

Sigma notation 1:

  10
<span>   Σ (2i + 3)
</span>i = 3

@ i = 3

2(3) + 3
12

The first sigma notation does not have the same result, so we move on to the next.

  10
<span>   Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.

When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)

Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.


3 0
3 years ago
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