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Yuki888 [10]
3 years ago
13

What’s the slope of the line??

Mathematics
1 answer:
kobusy [5.1K]3 years ago
6 0
The slope is -4/7
Take out two of the points.
(-7,1) (0,-3)
Now y2-y1/x2-x1
Which is -3-1/0-(-7)
That equals out to be -4/7
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John answered 80% of the questions correctly. There were 30 questions on the test. How many questions did John answer correctly?
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Answer:

he got 24 right

Step-by-step explanation:

30 time 80% is 24

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The equation of the line through point (-4,0) and parallel to the y-axis is
seraphim [82]

Answer:y=-4

Step-by-step explanation:

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What is 16 to 29 and 15 in at ratio
Semmy [17]
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Given the Homogeneous equation x^2ydy+xy^2dx=0, use y=ux, u=y/x and dy=udx+xdu to solve the differential equation. Solve for y.
scZoUnD [109]

Answer:

y=\frac{C}{x}.

Step-by-step explanation:

Given homogeneous equation

x^2ydy+xy^2dx=0

\frac{\mathrm{d}y}{\mathrm{d}x}=-\frac{xy^2}{x^2y}

Substitute y=ux , u=\frac{y}{x}

\frac{\mathrm{d}y}{\mathrm{d}x}=-\frac{y}{x}

Now,

u+x\frac{\mathrm{d}u}{\mathrm{d}x}=\frac{\mathrm{d}y}{\mathrm{d}x}

u+x\frac{\mathrm{d}u}{\mathrm{d}x}=-u

\frac{\mathrm{d}u}{\mathrm{d}x}=-2u

\frac{du}{u}=-\frac{dx}{x}

Integrating both side we get

lnu=-2lnx+lnC

Where lnC= integration constant

lnu+ln{x}^2=lnC

lnux^2=lnC

Cancel ln on both side

ux^2=C

Substitute u=\frac{y}{x}

Then we get

xy=C

y=\frac{C}{x}.

Answer:y=\frac{C}{x}.

8 0
3 years ago
Evaluate the following expression: (-5)(6) + (-6) ÷ (-3). Remember to show your work
Vinil7 [7]

Answer:

-28

Step-by-step explanation:

(-5)(6) + (-6) ÷ (-3) =

-30 + (-6) ÷ (-3) =

-30 + 2 =

-28

<em>Hope that helps! :)</em>

<em></em>

<em>-Aphrodite</em>

7 0
3 years ago
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