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2 years ago

1. Number the following steps of the quantum leap process in order from beginning to end.

Chemistry

1 answer:

kari74 [83]2 years ago

5 0

Answer:

1. Atom absorbs energy from a source

2. Electron becomes unstable because it is quantized

3. Electron jumps to a higher energy level

4. Energy is released in the form of light

5. Electron falls to a lower energy level

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Each year as the weather gets cold, gray whales swim over 10.000 miles from arctic waters south to coastal areas of

Svetradugi [14.3K]

Answer:

external

migration

Explanation:

4 0

3 years ago

How long is 5 half lives if the half life is 2.6 hours? Remember to round to the correct number of significant figures and use u

Dmitry [639]

Answer:

$\Delta t = 13\,h$

Explanation:

Half time is period required to desintegrating the half of the initial number of atoms. Then, the total time is:

$\Delta t = 5\cdot (2.6\,h)$

$\Delta t = 13\,h$

3 0

3 years ago

Needs to be answered ASAP <br><br> What group of protists does Euglena belong to? Why?

Korvikt [17]

Euglena belongs to the Kingdom Protista. It is a genus of single-celled flagellates. Euglena are the best known organisms in the Euglenophyta Phylum.Euglena belongs to the Kingdom Protista.<span> It is a genus of single-celled flagellates. Euglena are the best known organisms in the Euglenophyta Phylum.</span>

8 0

3 years ago

Assume the hydrolysis of ATP proceeds with ΔG′° = –30 kJ/mol. ATP + H2O → ADP + Pi Which expression gives the ratio of ADP to AT

Andru [333]

Answer:

$6.14\cdot 10^{-6}$

Explanation:

Firstly, write the expression for the equilibrium constant of this reaction:

$K_{eq} = \frac{[ADP][Pi]}{ATP}$

Secondly, we may relate the change in Gibbs free energy to the equilibrium constant using the equation below:

$\Delta G^o = -RT ln K_{eq}$

From here, rearrange the equation to solve for K:

$K_{eq} = e^{-\frac{\Delta G^o}{RT}}$

Now we know from the initial equation that:

$K_{eq} = \frac{[ADP][Pi]}{ATP}$

Let's express the ratio of ADP to ATP:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}}$

Substitute the expression for K:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}}$

Now we may use the values given to solve:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}} = [Pi]e^{\frac{\Delta G^o}{RT}} = 1.0 M\cdot e^{\frac{-30 kJ/mol}{2.5 kJ/mol}} = 6.14\cdot 10^{-6}$

7 0

3 years ago

NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a

Tanya [424]

Answer:

A = 0.023 m

Explanation:

The relation between the frequency of a radiation and its wavelength is given by the following expression.

where,

c is the speed of light (it has a constant value of 3.00 x 108 m/s)

A is the wavelength of the radiation v is the frequency of the radiation

In this case, the frequency is 13 GHz = 13 x

10° Hz = 13 x 1o° s-

The wavelength associated with this frequency is:

A = c/v = (3.00 x 10° m/s)/(13 x 10° s-") = 0.023

8 0

3 years ago