Which answer is it for number 7

Chemistry

1 answer:

Bess [88]2 years ago

7 0

Answer:

The answer is I

The 4 one represents Solids coz in solids atoms are tightly packed

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The correct mathematical expression for finding the molar solubility (s) of calcium phosphate is

GalinKa [24]

Answer is: The molar solubility of calcium phosphate is 108s⁵ = Ksp.

Balanced chemical reaction: Ca₃(PO₄)₂(s) → 3Ca²⁺(aq) + 2PO₄³⁻(aq).
[Ca²⁺] = 3s(Ca₃(PO₄)₂) = 3s.
[PO₄³⁻] = 2s.
Ksp = [Ca²⁺]³ · [PO₄³⁻]².
Ksp = (3s)³ · (2s)².
Ksp = 108s⁵.

s = ⁵√(Ksp ÷ 108).

6 0

3 years ago

Please answer each:) <3

Nutka1998 [239]

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4 0

2 years ago

If you have 100 ml of a 0.10 m tris buffer (pka 8.3) at ph 8.3 and you add 3.0 ml of 1.0 m hcl, what will be the new ph?

sukhopar [10]

The new pH is 7.69.

According to Hendersen Hasselbach equation;

The Henderson Hasselbalch equation is an approximate equation that shows the relationship between the pH or pOH of a solution and the pKa or pKb and the ratio of the concentrations of the dissociated chemical species. To calculate the pH of the buffer solution made by mixing salt and weak acid/base. It is used to calculate the pKa value. Prepare buffer solution of needed pH.

pH = pKa + log10 ([A–]/[HA])

Here, 100 mL of 0.10 m TRIS buffer pH 8.3

pka = 8.3

0.005 mol of TRIS.

∴ $8.3 = 8.3 + log \frac{[0.005]}{[0.005]}$

inverse log 0 = $\frac{[B]}{[A]}$

$\frac{[B]}{[A]} = 1$

Given; 3.0 ml of 1.0 m hcl.

pka = 8.3

0.003 mol of HCL.

$pH = 8.3 + log \frac{[0.005-0.003]}{[0.005+0.003]}\\pH = 8.3 + log \frac{[0.002]}{[0.008]}\\\\pH = 8.3 + log {0.25}\\\\pH = 8.3 + (-0.62)\\pH = 7.69$