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2 years ago

Marks: 1

Physics

1 answer:

____ [38]2 years ago

6 0

Answer:

W = 5W

Explanation:

1W = 1J/s

W = Watts

J = Joules

s = seconds

W = J/s

W = 300J/60s

W = 5W

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Which of the following statements are true? Select all that apply.

beks73 [17]

Answer:

The following options are true based on the properties of electric field;

a) Electric field lines near positive point charges radiate outward.

b) The electric force acting on a point charge is proportional to the magnitude of the point charge.

d) In a uniform electric field, the field lines are straight, parallel, and uniformly spaced.

Explanation:

From option b) From coulomb's law F = Kq1q2r/r2

5 0

3 years ago

How fast is a 90kg man running if his kinetic energy is 720 J?

zheka24 [161]

Answer:
4 m/s
Explanation:
KE=1/2mv^2
720=1/2(90)
720=45v^2
divide by 45
16= v^2
over the square root
4=v
v= 4m/s

6 0

3 years ago

A straight wire 0.10 m long carrying a current of 2.0 A is at right angles to a magnetic field. The force on the wire is 0.04 N.

Vladimir79 [104]

Answer:

The strength of magnetic field is 0.2 Tesla.

Explanation:

Data from the question is

Length (L) of wire ; L=0.10 m

Current in wire ; I= 2.0 A

Force on wire ; F = 0.04 N

Angle = Right angle So, $\theta$ $\thita = 90^{o}$

Now ,

We have to find the magnetic Field strength (B)

For this formula for Force on wire in magnetic field is

$F = I \times B \times L \times sin(\theta)$

Further modified as

$B = \frac{F}{I \times L \times sin(\theta)}$

Now insert values in the formula

$B = \frac{0.04N}{2.0A \times 0.10 m \times sin(90^{0})}$

$B = 0.2 T$

So, the strength of magnetic field is 0.2 Tesla.

8 0

3 years ago

A 9 newtwon charge is Felt on a (1x10^-4) C charge from another charge that is 3 meters away. What is the magnitude of that othe

Marina86 [1]

The magnitude of that other charge will be 9×10⁻⁵ C. The force on the charge is inverse of the distance.

<h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The magnitude of that other charge is found as;

$\rm F = \frac{Kq_1q_2}{r^2} \\\\ \rm 9 = \frac{9 \times 10^9 \times 1\times 10^{-4}\times q_2}{(3)^2} \\\\ q_2=9\times 10^{-5} \ C$

Hence, the magnitude of that other charge will be 9×10⁻⁵ C.

To learn more about Columb's law, refer to the link;

brainly.com/question/1616890

#SPJ1

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2 years ago

If there is an attractive force between all objects, why do we not feel ourselves gravitating toward massive buildings in our vi

mars1129 [50]

The mass of an object affects how powerful the attractive force is. To feel the pull / gravitation the mass of the object would have to be huge, bigger than that of massive buildings

8 0

3 years ago

Read 2 more answers