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Serga [27]
3 years ago
8

What causes the phases of the Moon as seen from Earth?

Physics
2 answers:
Pavlova-9 [17]3 years ago
6 0

Answer:

A-Light from the Sun reflects off the Moon as it orbits Earth

Explanation:

The cause of phases of the Moon as seen from Earth is when light from the Sun reflects off the Moon as it orbits Earth.

KIM [24]3 years ago
4 0

Answer:

A-Light from the Sun reflects off the Moon as it orbits Earth

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I am confused. Magnetic flux linkage and magnetic flux don't have the same definition, but they have same units. But there formu
ss7ja [257]

Answer:

magnetic flux linkage includes number of turns, N while magnetic flux has no N

Since number of turns are not significant to units, they become similar.

6 0
2 years ago
Explain why a book placed on a table does not move?
kifflom [539]

Answer:

The force that the book exerts down on the table is equal to the force the table exerts upward.

Explanation:

I am 100% positive. That results in balanced forces which is why it does not move. If you did want it to move, you would apply unbalanced forces.

4 0
3 years ago
Read 2 more answers
What is one main difference between animal cells and plant cells?
vekshin1

Answer:

No cell wall

Explanation:

7 0
2 years ago
Kawas 200 osebanywhes he remembered he had to return some books they​
tia_tia [17]
I think you need to add more.. but I may know where you are leading

Was he 200 m away and made the trip in 200 seconds?

If yes...
2 m/s was his speed and 0 velocity
6 0
3 years ago
The length of a certain wire is kept same while its radius is doubled. what is the new resistivity of this wire?
anastassius [24]
The text does not specify whether the resistance R of the wire must be kept the same or not: here I assume R must be kept the same.

The relationship between the resistance and the resistivity of a wire is
\rho =  \frac{AR}{L}
where
\rho is the resistivity
A is the cross-sectional area
R is the resistance
L is the wire length

the cross-sectional area is given by
A=\pi r^2
where r is the radius of the wire. Substituting in the previous equation ,we find
\rho =  \frac{\pi r^2 R}{L}

For the new wire, the length L is kept the same (L'=L) while the radius is doubled (r'=2r), so the new resistivity is
\rho' =  \frac{\pi r'^2 R}{L'}= \frac{\pi (2r)^2 R}{L}=4  \frac{\pi r^2 R}{L}   = 4 \rho
Therefore, the new resistivity must be 4 times the original one.
5 0
3 years ago
Read 2 more answers
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