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sashaice [31]
2 years ago
6

Which of the following should a scalar measurement have?

Physics
1 answer:
Nikolay [14]2 years ago
7 0
The scalar measurement or product is the magnitude because you are measuring the value
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A 55-liter tank is full and contains 40kg of fuel. Find using Sl units: • Density p. • Specific Weight y • Specific Gravity Answ
inna [77]

Answer:

Density of the fuel is 727.3 kilograms per cubic meter.

Specific weight of the fuel is 7127.3 Newtons per cubic meter.

Specific gravity of the fuel is 0,727.

Explanation:

In order to use SI units, we have to convert liters to cubic meters. Knowing that a liter is a cubic decimeter and a cubic decimeter is 1*10^{-3} cubic meters, we know that the tank has 0,055 cubic meters of fuel (because it is full).

Now that we have things in SI units, we calculate density:

p_{fuel}= \frac{mass}{volume} = \frac{40 kg}{0.055 m^{3} } =727.3 \frac{kg }{m^{3} }

Knowing the mass per unit of volume, we can calculate weight per unit of volume thanks to Newton's second law (mass times acceleration, g in this case, equals force (weight)), i.e. specific weight:

y=p*g=727,3 \frac{kg}{m^{3}}*9.8\frac{m }{s^{2}}=7127,3 \frac{N}{m^{3}}

With density we can also calculate how dense the fuel is related to a reference (water), i.e. specific gravity. SG is a dimensionless number that tell us how much denser (SG>1) or lighter per unit of volume (SG<1) a substance is than water. We use water as a reference because it is one of the most used substances in our life, and it is a standard density (1000 kg per cubic meter at 4°C and 1 atm).

SG=\frac{p_{fuel} }{p_{water} } =\frac{727.3 \frac{kg }{m^{3} }}{1000 \frac{kg }{m^{3} }} =0,727

7 0
3 years ago
The point during heat transfer at which both materials or objects are the same temperature.
Blizzard [7]

Answer:

Transferring

Explanation:

It's just the transferring of heat

4 0
3 years ago
The Dodgers are up at bat during the World Series. Joc Pederson swings his baseball bat and it collides perfectly with the baseb
arsen [322]

Answer:

According to Newton's third law, for every action force there is an equal (in size) and opposite (in direction) reaction force. ... The baseball forces the bat to the left; the bat forces the ball to the right. Together, these two forces exerted upon two different objects form the action-reaction force pair.

8 0
2 years ago
A helicopter carries a 1000-kg-car suspended from a rope below it. The helicopter flies horizontally at a constant speed of 25 m
kolbaska11 [484]

Answer:

(a) Tension, T = 28.653 kN

(b) Wind resistance force, 26.925\ kN

Solution:

As per the question:

Mass of the car, m = 1000 kg

Speed of the helicopter, v = 25 m/s

Angle made by the rope, theta = 20^{\circ}

Now,

(a) To calculate the tension, T in the car:

Tension along the direction of motion, T_{h} = Tcos20^{\circ}

Tension along the vertical direction, T_{v} = Tsin20^{\circ}

Now, let the force due to the wind directed in the opposite direction of the motion be F_{W} and it balances the horizontal component of the tension, T.

The vertical component is balance by the weight of the car, i.e., mg that acts vertically downwards.

Now,

T_{v} = mg

Tsin20^{\circ} = 1000\times 9.8

T = 28653 N = 28.653 kN

(b) The force of the wind resistance:

F_{W} = T_{h}

F_{W} = 2cos20^{\circ} = 26925\ N = 26.925\ kN

(c) Now,

  • If the angle made by the rope with the vertical is 0^{\circ}:

mg = Tsin(90^{\circ} - 0^{\circ})

Tsin90^{\circ} = mg = 9800\ N

The tension in the rope will be equal to the weight the car.

Wind resistance force, F_{W} = Tcos90^{\circ} = 0\ N

  • If the angle made by the rope with the vertical is 90^{\circ}:

mg = Tsin(90^{\circ} - 90^{\circ})

T = 0 N

Wind resistance force, F_{W} = Tsin0^{\circ}

Tsin0^{\circ} = mg

F_{W} = \infty

There will be no tension in the rope and wind resistance will be infinite.

3 0
3 years ago
You are given a semiconductor resistor made from silicon with an impurity concentration of resistivity 1.00×10−3ωm. the resistor
Vlad [161]

Answer: Resistance =3.2 \Omega , Current = 1.56 A, Voltage =4.99 V

The resistance,

R=\frac {\rho l}{A}

where, \rho is resistivity, A is the area and l is the length of the resistor.

It is given that:

\rho=1.0\times10^{-3}\Omega m

Length, l=2 mm

Area, A= width \times height=1.25 mm\times 0.5 mm=0.625 mm^2

Hence, R=\frac{1.0\times10^{-3}\Omega m \times 2\times10^{-3}m}{0.625\times10^{-6}m^2}=3.2\Omega

We know, Power, P=I^2R

\Rightarrow I=\sqrt{\frac{P}{R}}

P=7.81 W

I=\sqrt{\frac {7.81 W}{3.2\Omega}}=\sqrt{2.44}A=1.56A

We know, Voltage, V=IR=1.56\times3.2=4.99 V




4 0
2 years ago
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