Answer:
The answer to your question is: Iron oxidizes and Copper reduces
Explanation:
An element oxidizes when it loses electrons
An element reduces when it gains electrons
Then
Fe ⇒ Fe⁺² Now, is more positive, it loses electrons
Cu⁺² ⇒ Cu Now, is more negative, it gains electrons
Iron oxidizes and Copper reduces
D atoms that are in only one of the reactions and only one of the products should be down first
Explanation:
The sum of all oxidation numbers in a neutral compound is zero. The sum of all oxidation numbers in a polyatomic (many-atom) ion is equal to the charge on the ion. The oxidation number of oxygen in a compound is usually –2. The oxidation state of hydrogen in a compound is usually +1.
The oxidation state of Al in Al(OH)
4
−
x+4(+1−2)=−1
∴x=+3
The oxidation state of Mn in MnO
2
y+2(−2)=0
∴y=+4
thank u