Which compound has the bigger lattice energy? K Br CaBr2 o O Na, NaF Rb20 0 Rb, S 0

Chemistry

1 answer:

HACTEHA [7]3 years ago

4 0

Answer:

The answer is NaF.

Explanation:

Lattice energy:

It can be define as "the amount of energy released when ions combine to from the ionic solids or energy required to break the compound into its ions"

Example:

Consider the example of ionic solid NaCl. The sodium chloride is formed when ions like Na+ and Cl - are combine. During the formation of NaCl crystals the energy is released which is called lattice energy of sodium chloride.

Dependence of lattice energy:

Lattice energy depend upon following factors:

1. Charges of the ions

2. Sizes of the ions

As the charge of ion increase the lattice energy also increase. There is a direst relationship between them.

The size of the ions and lattice energy have inverse relation. As the size decreases, lattice energy increases. Therefor, the compound NaF consist of smallest cation (Na+) and the smallest anion (F-) have largest lattice energy.

F= q1 × q2/ r²

As the size of ions decreases the distance between the oppositely charged ions in a ionic compound decreases. They will more tightly packed in a crystal and their center will more closer to each others hence increase the lattice energy.

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If 5.58 g of iron reacts with sulfur to produce 8.79 g of iron sulfide, what is the mass of reacting sulfur? A) 3215 B) 14:37 C)

gogolik [260]

Answer: A) 3.21 g

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side.

$Fe+S\rightarrow FeS$

We are given:

Mass of iron = 5.58 g

Mass of iron sulphide = 8.79 g

Mass of sulphur = x g

Total mass on reactant side = 5.58 + x

Total mass on product side = 8.79 g

Applying law of conservation of mass, we get:

$5.58+x=8.79\\\\x=3.21g$

Hence, the mass of reacting sulfur is 3.21 g.

7 0

3 years ago

Is the law of conservative mass observed in this equation CaCO3 + 2HCI -->CaCI2 +H2O + CO2

pychu [463]

Answer:

The law is observed in the given equation.

Explanation:

CaCO₃ + 2HCI → CaCI₂ +H₂O + CO₂

In order to find out if the law of conservative mass is followed, we need to <u>count how many atoms of each element are there in both sides of the equation</u>: