Answer:
Using linkedlist on C++, we have the program below.
Explanation:
#include<iostream>
#include<cstdlib>
using namespace std;
//structure of linked list
struct linkedList
{
int data;
struct linkedList *next;
};
//print linked list
void printList(struct linkedList *head)
{
linkedList *t=head;
while(t!=NULL)
{
cout<<t->data;
if(t->next!=NULL)
cout<<" -> ";
t=t->next;
}
}
//insert newnode at head of linked List
struct linkedList* insert(struct linkedList *head,int data)
{
linkedList *newnode=new linkedList;
newnode->data=data;
newnode->next=NULL;
if(head==NULL)
head=newnode;
else
{
struct linkedList *temp=head;
while(temp->next!=NULL)
temp=temp->next;
temp->next=newnode;
}
return head;
}
void multiplyOddPosition(struct linkedList *head)
{
struct linkedList *temp=head;
while(temp!=NULL)
{
temp->data = temp->data*10; //multiply values at odd position by 10
temp = temp->next;
//skip odd position values
if(temp!= NULL)
temp = temp->next;
}
}
int main()
{
int n,data;
linkedList *head=NULL;
// create linked list
head=insert(head,20);
head=insert(head,5);
head=insert(head,11);
head=insert(head,17);
head=insert(head,23);
head=insert(head,12);
head=insert(head,4);
head=insert(head,21);
cout<<"\nLinked List : ";
printList(head); //print list
multiplyOddPosition(head);
cout<<"\nLinked List After Multiply by 10 at odd position : ";
printList(head); //print list
return 0;
}
Answer:
umax = 0.1259ft/s
Explanation:
Given:
•Distance between plates, B = 0.01ft
•Pressure difference decrease, 
•Fluid viscosity, u = 10^-³lbf-s/ft²
Specific gravity, S = 0.80
Max velocity in the z-direction will be:
![u_max= [\frac{B^2y}{8u}]\frac{dh}{ds}](https://tex.z-dn.net/?f=u_max%3D%20%5B%5Cfrac%7BB%5E2y%7D%7B8u%7D%5D%5Cfrac%7Bdh%7D%7Bds%7D)
Substituting for h in the first equation, we have:
![\frac{d}{dz}[\frac{p}{y}+z]](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdz%7D%5B%5Cfrac%7Bp%7D%7By%7D%2Bz%5D)
= -0.20192
Substituting dh/dz value in the first equation (umax), we have:
umax = 0.1259ft/s
