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3 years ago

Select the properties and typical applications for the high carbon steels.

Engineering

1 answer:

yanalaym [24]3 years ago

3 0

Answer:

Option-(A)

Explanation:

Typical applications for the high carbon steels includes the following;

It is heat treatable, relatively large combinations of mechanical characteristics. Typical applications: railway wheels and tracks, gears, crankshafts, and machine parts.

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Write a program that uses the function isPalindrome given below. Test your program on the following strings: madam, abba, 22, 67

defon

Answer:

#include <iostream>

#include <string>

using namespace std;

bool isPalindrome(string str)

{

int length = str.length();

for (int i = 0; i < length / 2; i++)

{

if (tolower(str[i]) != tolower(str[length - 1 - i]))

return false;

}

return true;

}

int main()

{

string s[6] = {"madam", "abba", "22", "67876", "444244", "trymeuemyrt"};

int i;

for(i=0; i<6; i++)

{

//Testing function

if(isPalindrome(s[i]))

{

cout << "\n " << s[i] << " is a palindrome... \n";

}

else

{

cout << "\n " << s[i] << " is not a palindrome... \n";

}

return 0;

}

5 0

3 years ago

A 1-ft rod with a diameter of 0.5 in. is subjected to a tensile force of 1,300 lb and has an elongation of 0.009 in. The modulus

iragen [17]

Answer:

E = 8.83 kips

Explanation:

First, we determine the stress on the rod:

$\sigma = \frac{F}{A}\\\\$

where,

σ = stress = ?

F = Force Applied = 1300 lb

A = Cross-sectional Area of rod = 0.5 $\pi \frac{d^2}{4} = \pi \frac{(0.5\ in)^2}{4} = 0.1963\ in^2$

Therefore,

$\sigma = \frac{1300\ lb}{0.1963\ in^2} \\\\\sigma = 6.62\ kips$

Now, we determine the strain:

$strain = \epsilon = \frac{elongation}{original\ length} \\\\\epsilon = \frac{0.009\ in}{12\ in}\\\\\epsilon = 7.5\ x\ 10^{-4}$

Now, the modulus of elasticity (E) is given as:

$E = \frac{\sigma}{\epsilon}\\\\E = \frac{6.62\ kips}{7.5\ x\ 10^{-4}}$

E = 8.83 kips

7 0

3 years ago

1. Select the punch that is used to make a mark in metal

s344n2d4d5 [400]

Answer:

pin punch

Explanation:

Pin Punch 
 pin punch

8 0

3 years ago

A single phase, 50-KVA, 2400-240-volt, 60 Hz distribution transformer has the following parameters: •

never [62]

Answer:

B) voltage at the sending end of the feeder = 2483.66 v

Explanation:

attached below is the the equivalent circuits and the remaining solution for option A

B) voltage = 2400 v

I = $\frac{50*10^3}{2400}$ = 20.83 A

calculate voltage at sending end ( Vs )

Vs = 2400 + 20.83 ∠ -cos^-1 (0.8) ( 0.75*2 + 0.5 + j 2 + j2 )

hence Vs = 2483.66 ∠ 0.961

therefore voltage at the sending end = 2483.66 v

8 0

3 years ago

The size of a hose is the ____ of the hose

drek231 [11]

Explanation:

inside diameter of the hose

6 0

3 years ago