The solution to your problem is as follows:
<span>2 KClO3 → 2 KCl + 3 O2
</span><span>MW of KCL = 39.1 + 35.35 = 74.6 g/mole
62.6/74.6 = 0.839 moles KCl produced
0.839 moles KCl x 3O2/2KCl x 32g/mole O2 = 40.27g of O2 was produced
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Therefore, there are <span>40.27g of O2 produced during the reaction.
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I hope my answer has come to your help. Thank you for posting your question here in Brainly.
Neon is the element that is classified as a noble gas at STP.
This polarity makes water molecules attracted to each other. The oxygen-hydrogen bond in the alcohol molecule is also polar. But, the carbon hydrogen bonds in the rest of the alcohol molecule are nonpolar. In these bonds, the electrons are shared more or less evenly.
[Ar] 3d10 4s2 4p5 is the electron configuration of bromine
3Na2O(at) + 2Al(NO3)3(aq) —> 6NaNO3(aq) + Al2O3(s)
This is a double replacement reaction and NaNO3 is aqueous because Na is an alkali metal, plus nitrate is in the solution. Both of these are soluble. Al2O3 is not soluble because it does not contain any element that is soluble and is hence the precipitate.
Hope this helped!
