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Evgen [1.6K]
1 year ago
11

Identify the chemical symbols corresponding to each element. drag the appropriate labels to their respective targets.

Chemistry
1 answer:
Shalnov [3]1 year ago
8 0

The name and chemical symbol of the elements are

  • Carbon = C
  • Lead = Pb
  • Antimony = Sb
  • Sodium = Na
  • Aluminum = Al

<h3>What are chemical symbols?</h3>

Chemical symbols are which are used to represent the elements in the periodic table.

The chemical symbol assigned to elements are usually an abbreviation of the name of the element or the Latin form of the name.

The name and symbol of the given elements are as follows:

  • Carbon = C
  • Lead = Pb
  • Antimony = Sb
  • Sodium = Na
  • Aluminum = Al

The chemical symbols are used frequently in writing the formula of compound formed from the elements. For example, the compound sodium aluminate which contains sodium, aluminum and oxygen is written in a simplified form as: NaAlO₂.

Learn more about chemical symbols at: brainly.com/question/118939

#SPJ1

Note that the complete question is given below:

Part A

Identify the chemical symbols corresponding to each element Drag the appropriate labels to their respective targets.

View Available Hint(s)

Element

Carbon

Lead

Antimony

Sodium

Aluminum

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<span>Answer: 0.00649M


The question is incomplete,
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<span>You are told that the first ionization of the sulfuric acid is complete and the second ionization of the sulfuric acid has a constant Ka₂ = 0.012
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With that you can solve the question following these steps"
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<span>1) First ionization:
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Under the fully ionization assumption the concentration of HSO4- is the same of the acid = 0.01 M


2) Second ionization
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<span>HSO₄⁻ (aq) ⇄ H⁺ + SO₄²⁻ with a Ka₂ = 0.012
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<span>Do the mass balance:
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<span><span>        HSO₄⁻ (aq)        H⁺        SO₄²⁻</span>
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<span /><span /><span>        0.01 M  - x          x            x


</span><span>Ka₂ = [H⁺] [SO₄²⁻] / [HSO₄⁻]</span>
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<span>3) Solve the equation:


</span><span>x² = 0.012(0.01 - x) = 0.00012 - 0.012x</span>
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x² + 0.012x - 0.0012 = 0
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<span>Using the quadratic formula: x = 0.00649
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<span>So, the requested concentratioN is [SO₄²⁻] = 0.00649M</span>

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