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pishuonlain [190]
3 years ago
11

Two trains leave the same station at the same time, but are headed in opposite directions. One train travels at 70 mph and the o

ther train travels at 80 mph.
How much time passes until the trains are 600 mi apart?
Mathematics
1 answer:
Umnica [9.8K]3 years ago
7 0
70t + 80t = 600
150t = 600 Simplify
t = 4 Divide
70(4) + 80(4) = 600 Check

4 hours
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Help....................
Romashka-Z-Leto [24]

Answer:

The interquartile range is <em>50.</em>

Step-by-step explanation:

To find our answer we have to first <em>quartile 1</em> and <em>quartile 3</em> are equal too. When we look at the plot <em>quartile 1  </em>is equal to <em>20,</em> <em>quartile 3 </em>is equal to <em>70</em> because it is in between <em>60</em> and <em>80</em>.  Now to find the interquartile range we will <em>subtract 70</em> from <em>20</em> and we get <em>50</em>.  Therefore, <u><em>50</em></u><em> is our answer.</em>

7 0
3 years ago
Read 2 more answers
In a grade seven class, 18 students have pets, and 12 do not. What percent of the class has a pet?
Svetradugi [14.3K]
Answer :
If 18+12 is 30 and only 18 of them has pets then 70 percent have pets
7 0
3 years ago
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Someone help lolz..​
Mkey [24]
The answer is y =-4 !
6 0
3 years ago
Given the functions k(x) = 2x2 − 7 and p(x) = x − 4, find (k ∘ p)(x). (k ∘ p)(x) = 2x2 − 8x + 16 (k ∘ p)(x) = 2x2 − 16x + 32 (k
Anuta_ua [19.1K]

Answer:

<h2>(k ∘ p)(x) = 2x² - 16x + 25</h2>

Step-by-step explanation:

k(x) = 2x² - 7

p(x) = x - 4

To find (k ∘ p)(x) substitute p(x) into k(x),

that's replace any x in k(x) by p(x)

We have

(k ∘ p)(x) = 2(x - 4)² - 7

Expand

(k ∘ p)(x) = 2( x² - 8x + 16) - 7

= 2x² - 16x + 32 - 7

Simplify

We have the final answer as

<h3>(k ∘ p)(x) = 2x² - 16x + 25</h3>

Hope this helps you

3 0
3 years ago
16+(18+10)=(x+18)+10
sasho [114]
16 + 18 + 10 = 44
44 = x + 28
16 = x
x = 16
4 0
3 years ago
Read 2 more answers
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