Explanation:
An perfect mass less spring, attached at one end and with a free mass attached at the other end, will have a distinct frequency of oscillation depending on its constant spring and mass. On the other hand, a spring with mass along its length will not have a characteristic frequency of oscillation.
Alternatively, based on its spring constant and mass per length, it will now have a wave Speed. It would be possible to use all wavelengths and frequencies, as long as the component fλ= S, where S is the spring wave size. If that sounds like longitudinal waves, like solid sound waves.
Sweat is slightly acidic which helps to protect the body.
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Work is force times distance. If there's no distance, there's no work being done.
A spinning top is the answer
Answer:
The time is 106.7 minute.
Explanation:
Given that,
Density 
Current 
Diameter of wire = 1.2 mm
Length = 31 cm
We need to calculate the drift velocity
Using formula of drift velocity


Put the value into the formula


We need to calculate the time
Using formula for time


Where, l = length
= drift velocity
Put the value into the formula



Hence, The time is 106.7 minute.