We have that the instantaneous velocity of the
shuttlecock when it hits the ground is
From the question we are told
Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the
shuttlecock when it hits the ground? Show your work below.
Generally the equation for acceleration is mathematically given as
Where
acceleration is still -9.81 m/s2,
Hence,
Therefore
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Answer:
x=?
dt=?
vi=23m/s
vf=0m/s (it stops)
d=0.25m/s^2
time =
vf=vi+d: 0=23m/s+(0.25m/s^2)t
t=92s
displacement=
vf^2=vi^2+2a(dx)
23^2=0^2+2(0.25m/s^2)x =-1058m
Explanation:
you can find time from vf = vi + a(Dt): 0 = 23 m/s + (0.25 m/s/s)t so t = 92 s and you can find the displacement from vf2 = vi2 + 2a(Dx) and find the answer in one step: 232 = 02 + 2(0.25 m/s/s)x so x = -1058 m
Answer:
They are the smallest pancise of any matere
Answer:
1. 10.5 Kg
2. s/g
Explanation:
1. Determination of the mass of gasoline
Density of gasoline = 0.7 Kg/L
Volume of gasoline = 15 L
Mass of gasoline =?
The density of a substance is simply defined as the mass of the substance per unit volume of the substance. Mathematically, the density of a substance can be expressed as:
Density = mass / volume
With the above formula, we can obtain the mass of the gasoline as follow:
Density of gasoline = 0.7 Kg/L
Volume of gasoline = 15 L
Mass of gasoline =?
Density = mass / volume
0.7 = Mass of gasoline / 15
Cross multiply
Mass of gasoline = 0.7 × 15
Mass of gasoline = 10.5 Kg
2. Density has various units some are listed below:
I. Kilogram per litre (Kg/L)
II. Kilogram per cubic metre (Kg/m³)
III. Milligram per millilitre (mg/mL)
IV. Gram per millilitre (g/mL)
V. Gram per cubic centimetre (g/cm³)
Considering the options given in the question above, it is evident that second per gram (s/g) is not a unit of density because density is mass per unit volume.
