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chubhunter [2.5K]
3 years ago
15

What is the acceleration of this object? The object's mass is 60 kg.

Physics
2 answers:
Licemer1 [7]3 years ago
5 0
First determine the net force. Let's say the downwards force is negative and the upwards force is positive.
Since the forces act in opposite directions, the net force would be:
400N - 600N = -200N

Since I said negative is downwards, this translates to the net force being 200N downwards.

Force = mass*acceleration
200N = 60kg * acceleration
acceleration = 3.33 m/s^2
tigry1 [53]3 years ago
4 0

3.3 m/s2


i took the test ;)

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Fynjy0 [20]
D.
The reading between 7N and 8N would have to be 7.5N. Answers A and B are much to small and answer C is way to big.
8 0
3 years ago
Read 2 more answers
Suppose a person pushes thumbtack that is 1/5 centimeter long into a bulletin board, and the force (in dynes) exerted when the d
mario62 [17]

Answer:

W = 290.7 dynes*cm

Explanation:

d = 1/5 cm = 0.2 cm

The force is in function of the depth x:

F(x) = 1000 * (1 + 2*x)^2

We can expand that as:

F(x) = 1000 * (1 + 4*x + 4x^2)

F(x) = 1000 + 4000*x + 4000*x^2

Work is defined as

W = F * d

Since we have non constant force we integrate

W = \int\limits^{0.2}_{0} {(1000 + 4000*x + 4000*x^2)} \, dx

W = [1000*x + 2000*x^2 + 1333*X^3] evaluated between 0 and 0.2

W = 1000*0.2 + 2000*0.2^2 + 1333*0.2^3 - 1000*0 - 2000*0^2 - 1333*0^3

W = 200 + 80 + 10.7 = 290.7 dynes*cm

3 0
3 years ago
An airplane is heading south at a speed of 600km/h. If a wind begins blowing from the southwest at a speed of 100km/h, calculate
Karo-lina-s [1.5K]

Answer:

Here's what I got:

Let's assume that N and E are + directions while S and W are - directions.

Wind is blowing from SW; thus, it is blowing towards NE (or at 45 deg N of E).

Dividing the wind's speed into components:y-component: +70.71 km/h; x-component: +70.71 km/h

Dividing the airplane's speed into components:y-component: -600 km/h; x-component: 0 km/h

Adding the components to get the resulting components:y-component: -529.29 km/h; x-component: +70.71

Using the Pythagorean Theorem to find the resulting speed:v^2 = y^2 + x^2 so v = 533.99 km/h

To find the angle of direction, use arctan (y/x):arctan (529.29/70.71) = 82.39 deg

ANSWER: velocity = 533.99 km/h at 82.39 deg S of E

Explanation:

8 0
3 years ago
Calculate the radius of the orbit of a proton moving at 2.2x10^6 m/s in a magnetic field 0.7 T where v and B are perpendicular.
Juliette [100K]

Answer:

3.28 cm

Explanation:

To solve this problem, you need to know that a magnetic field B perpendicular to the movement of a proton that moves at a velocity v will cause a Force F experimented by the particle that is orthogonal to both the velocity and the magnetic Field. When a particle experiments a Force orthogonal to its velocity, the path it will follow will be circular. The radius of said circle can be calculated using the expression:

r = \frac{mv}{qB}

Where m is the mass of the particle, v is its velocity, q is its charge and B is the magnitude of the magnetic field.

The mass and  charge of a proton are:

m = 1.67 * 10^-27 kg

q = 1.6 * 10^-19 C

So, we get that the radius r will be:

r =  \frac{1.67 * 10^-27 kg * 2.2*10^6 m/s}{1.6 * 10^-19 C* 0.7 T} = 0.0328 m, or 3.28  cm.

8 0
3 years ago
A mad scientist wants to collect massive amounts of charge on basketball sized aluminum balls. The scientist wants to place 6 C
vitfil [10]

The distance between two basket ball sized aluminium balls is 9714 m.

Explanation:

Coulomb's law, or Coulomb's inverse-square law, is an experimental law of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force .

Coulomb's law formula => F = (k * Qb1 * Qb2)/r²

Given data :-

charge on ball 1 Qb1 = 6C

charge on ball 2 Qb2 = 14C

Force exerted F = 8000 N

k =  8.988 x 10^9 Nm²C−²(coulomb's constant).

substituting given values in the coulomb's formula

8000 = (( 8.988 x 10^9)*6*14)/r²

shifting r and 8000 to other sides

r² = (756 * 10^9)/8000

r = 9714 m.

Therefore the distance between two balls is r = 9714 m.

4 0
3 years ago
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