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chubhunter [2.5K]
3 years ago
15

What is the acceleration of this object? The object's mass is 60 kg.

Physics
2 answers:
Licemer1 [7]3 years ago
5 0
First determine the net force. Let's say the downwards force is negative and the upwards force is positive.
Since the forces act in opposite directions, the net force would be:
400N - 600N = -200N

Since I said negative is downwards, this translates to the net force being 200N downwards.

Force = mass*acceleration
200N = 60kg * acceleration
acceleration = 3.33 m/s^2
tigry1 [53]3 years ago
4 0

3.3 m/s2


i took the test ;)

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The atoms ,molecules,or compound present at the start of a chemical reaction that parcitipate in the reaction . which part of a
Tomtit [17]

Answer:

The atoms ,molecules, or compound present at the start of a chemical reaction that parcitipate in the reaction are <u><em>the reactants.</em></u>

Explanation:

The chemical reaction is the way in which one substance reacts against another. So, a chemical reaction consists of the transformation of some substances into others, that is, the process of arranging atoms and bonds when chemical substances come into contact.

In a chemical reaction, the initial substances are called reactants, while the new substances obtained are called products.

So, <u><em>the atoms ,molecules, or compound present at the start of a chemical reaction that parcitipate in the reaction are the reactants.</em></u>

8 0
3 years ago
The greatest height reported for a jump into an airbag is 99.4 m by stuntman Dan Koko. In 1948 he jumped from rest from the top
leva [86]

Answer:

44.1613858478 m/s

Explanation:

t = Time taken

u = Initial velocity = 0

v = Final velocity

s = Displacement = 99.4

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² = a

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 99.4+0^2}\\\Rightarrow v=44.1613858478\ m/s

If air resistance was absent Dan Koko would strike the airbag at 44.1613858478 m/s

6 0
3 years ago
Two 1.9 kg masses are 1.1 m apart (center to center) on a frictionless table. Each has + 9.6 μC of charge.
Anni [7]

Answer:

F= 0.6 N

Explanation:

Fe(electrical force)=k q1q2/r^2

    k=9*10^9\\q1=-9.6 *10^-6 C\\q2= -9.6*10^-6 C\\r= 1.1m

So,    

        F=\frac{9*10^9*-9.6 *10^-6 C* -9.6*10^-6 C}{1.1^2}

         F= 0.6 N

5 0
3 years ago
A plank of length L=2.200 m and mass M=4.00 kg is suspended horizontally by a thin cable at one end and to a pivot on a wall at
Elenna [48]

The tension in the cable is 23.2 N

<h3>What is the tension in the string?</h3>

The tension in the cable can be resolved into horizontal and vertical forces Tcosθ and Tsinθ respectively.

Tcosθ, is acting perpendicularly, Tcosθ = 0

Taking moments about the pivot:

Tsinθ * 2.2 = 4 * 9.8 * 0.7

Solving for θ;

θ = tan⁻¹(1.4/2.2) = 32.5°

T = 27.44/(sin 32.5 * 2.2)

T = 23.2 N

In conclusion, the tension in the cable is determined by taking moments about the pivot.

Learn more about moments of forces at: brainly.com/question/23826701

#SPJ1

3 0
2 years ago
I NEED HELP RIGHT NOW PLEASE I will  30pts and A brainly to anyone who helps me with questions 2-13!!!!!!!
neonofarm [45]
True True False True False False True I hope I helped on the first few
3 0
3 years ago
Read 2 more answers
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