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chubhunter [2.5K]
3 years ago
15

What is the acceleration of this object? The object's mass is 60 kg.

Physics
2 answers:
Licemer1 [7]3 years ago
5 0
First determine the net force. Let's say the downwards force is negative and the upwards force is positive.
Since the forces act in opposite directions, the net force would be:
400N - 600N = -200N

Since I said negative is downwards, this translates to the net force being 200N downwards.

Force = mass*acceleration
200N = 60kg * acceleration
acceleration = 3.33 m/s^2
tigry1 [53]3 years ago
4 0

3.3 m/s2


i took the test ;)

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As additional resistors are connected in series to a constant voltage source, how is the power supplied by the source affected?
Furkat [3]

Answer:

(D) The power supplied by the source decreases.

Explanation:

If additional resistors are connected in series, then the total resistance of the circuit is increased. By the Ohm’s Law, V = iR, the current decreases.

The power supplied by the source is P = i*i*R = i*(i*R). The term in the parenthesis is the voltage of the circuit and is constant. The ‘i’ outside decreases, therefore the power supplied by the source decreases.

7 0
4 years ago
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An ideal gas is at a pressure 1.00 Ã 105 n/m2 and occupies a volume 2.00 m3. if the gas is compressed to a volume 1.00 m3 while
blsea [12.9K]
The behavior of an ideal gas at constant temperature obeys Boyle's Law of
p*V = constant
where
p = pressure
V = volume.

Given:
State 1:  
  p₁ = 10⁵ N/m² (Pa)
  V₁ = 2 m³
State 2:
  V₂ = 1 m³

Therefore the pressure at state 2 is given by
p₂V₂ = p₁V₁
or
p₂ = (V₁/V₂) p₁
    = 2 x 10⁵ Pa

Answer: 2 x 10⁵ N/m² or 2 atm.
4 0
3 years ago
Worried that your cat may be ambushed by a mountain lion, you build a fence around
julia-pushkina [17]

Answer:

there speed must be 180

3 0
3 years ago
A 295-kg object and a 595-kg object are separated by 4.10 m.
kodGreya [7K]

Answer:

a)F=3 x 10⁻⁷ N

b)x=2.405 m

Explanation:

Given that

m₁=295 kg

m₂=595 kg

d= 4.1 m

a)

m₃=63 kg

r=d/2 = 2.05 m

The force between the mass m₁ and m₃

F_{13}=\dfrac{Gm_1m_3}{r^2}

by putting the values

F_{13}=\dfrac{Gm_1m_3}{r^2}

F_{13}=\dfrac{6.67\times 10^{-11}\times 295\times 63 }{2.05^2}

F₁₃=2.94 x 10⁻⁷ N

The force  between the mass m₂ and m₃

by putting the values

F_{23}=\dfrac{Gm_2m_3}{r^2}

F_{23}=\dfrac{6.67\times 10^{-11}\times 595\times 63 }{2.05^2}

F₂₃=5.94 x 10⁻⁷ N

The net force F

F= F₂₃- F₁₃

F=5.94 x 10⁻⁷ N-2.94 x 10⁻⁷ N

F=3 x 10⁻⁷ N

b)

Lest take at distance x from mass m₂ net force is zero.

F_{23}=\dfrac{Gm_2m_3}{x^2}

F_{13}=\dfrac{Gm_1m_3}{(4.1-x)^2}

Form above two equation

\dfrac{Gm_1m_3}{(4.1-x)^2}=\dfrac{Gm_2m_3}{x^2}

\dfrac{m_1}{(4.1-x)^2}=\dfrac{m_2}{x^2}

\dfrac{295}{(4.1-x)^2}=\dfrac{595}{x^2}

x²=2.01(4.1-x)²

x=1.42 (4.1-x)

x=5.82 - 1.42x

x=2.405 m

4 0
3 years ago
Suppose you look at the huge clock on the Big Ben Tower in London and it reads 12 noon. If you could travel away from the clock
spin [16.1K]

Answer:

Option C. be frozen at 12 noon

Explanation:

This can be explained by the special theory of relativity according to which at greater speeds time slows down and length contracts in the direction of motion.

Also if a body travels at the speed of light time will stop and the body will will reduce to zero length.

Therefore, for the given case time will freeze at 12 noon.

7 0
3 years ago
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