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TEA [102]
3 years ago
8

An object has a mass of 7 kg and is accelerating at 4 m/s2. How far would the object move if it took 168 J of work to move it?​

Physics
1 answer:
KIM [24]3 years ago
6 0

Answer:

6m

Explanation:

use work =force×distance

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Differences between work against friction and work against gravity.
Goshia [24]

Friction is the force that is resisting the motion of an object so it will always point in the opposite direction of that of movement. ... The force of gravity points downwards . So when you do work against gravity it means that the force acting on that object points in the upward direction .

4 0
3 years ago
Read 2 more answers
The rectangular coils in a 345-turn generator are 12 cm by 12 cm. Part A
Likurg_2 [28]

Answer:

118.166 volt

Explanation:

We have given number of turns N =345

Sides of the rectangular coils is 12 cm =0.12 m

So area A =0.12×0.12=0.0144 m^2

Magnetic field B =0.45 T

Angular speed =505 rpm

Speed in rad/sec \omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 505}{60}=52.8566rad/sec

The emf is given by E=NAB\omega SIN\omega t

For maximum emf sinwt =1

So E=345\times 0.0144\times 0.45\times 52.8566=118.166volt

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3 years ago
Went to make a sandwich<br> what ingredients do I need
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4 years ago
You accidentally drop an eraser out of the window of an apartment 15 m above the ground
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Answer:

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3 0
3 years ago
Two identical loudspeakers 2.00 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standi
ki77a [65]

Answer:

The lowest possible frequency of sound for which this is possible is 1307.69 Hz

Explanation:

From the question, Abby is standing 5.00m in front of one of the speakers, perpendicular to the line joining the speakers.

First, we will determine his distance from the second speaker using the Pythagorean theorem

l₂ = √(2.00²+5.00²)

l₂ = √4+25

l₂ = √29

l₂ = 5.39 m

Hence, the path difference is

ΔL = l₂ - l₁

ΔL = 5.39 m - 5.00 m

ΔL = 0.39 m

From the formula for destructive interference

ΔL = (n+1/2)λ

where n is any integer and λ is the wavelength

n = 1 in this case, the lowest possible frequency corresponds to the largest wavelength, which corresponds to the smallest value of n.

Then,

0.39 = (1+ 1/2)λ

0.39 = (3/2)λ

0.39 = 1.5λ

∴ λ = 0.39/1.5

λ = 0.26 m

From

v = fλ

f = v/λ

f = 340 / 0.26

f = 1307.69 Hz

Hence, the lowest possible frequency of sound for which this is possible is 1307.69 Hz.

5 0
3 years ago
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