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Aliun [14]
3 years ago
9

The anemometer is spinning and the pressure us high

Physics
1 answer:
skelet666 [1.2K]3 years ago
3 0

Answer:

what help you need?????????

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Please complete it if you know the answer. "The active region of a transistor is for.........
zubka84 [21]

Answer:

the active region is bound by cutoff region and saturation or power dissipation region.

Explanation:

5 0
3 years ago
Calculate the wave speed i the wavelength =64m and the wave period = 4s
Marina86 [1]
To do this you would take 64 and divide it by 4.
64/4= 16. 
Your answer is 16.
8 0
3 years ago
After France fell to the Axis powers in 1940, what percentage of the country was placed under German control?
gogolik [260]

Correct answer choice is:

B. 50 percent

Explanation:

France Capitulates to Nazi Germany. On June 22, 1940, the French state approved a cease-fire with Nazi Germany just six weeks after the Nazis began their incursion of Western Europe.

Paris began preparing for combat in September 1939, when Nazi Germany overran Poland, but the combat appeared far beyond until May 10, 1940, when the Germans invaded France and immediately took the French troops. The French administration left Paris on June 10, and the Germans controlled the capital on June 14.

4 0
3 years ago
Read 2 more answers
A source of emf is connected by wires to a resistor, and electrons flow in the circuit. The wire diameter is the same throughout
Zina [86]

Answer:

C. the same.

Explanation:

The drift speed of electrons in a circuit is the same all through the circuit.

4 0
3 years ago
X-rays with an energy of 301 keV undergo Compton scattering with a target. If the scattered X-rays are detected at 77.5^{\circ}
Alex73 [517]

Answer:

6.03\cdot 10^{-12} m

Explanation:

First of all, we need to find the initial wavelength of the photon.

We know that its energy is

E=301 keV = 4.82\cdot 10^{-14}J

So its wavelength is given by:

\lambda = \frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4.82\cdot 10^{-14} J}=4.13\cdot 10^{-12}m

The formula for the Compton scattering is:

\lambda' = \lambda +\frac{h}{mc}(1-cos \theta)

where

\lambda is the original wavelength

h is the Planck constant

m is the electron mass

c is the speed of light

\theta=77.5^{\circ} is the angle of the scattered photon

Substituting, we find

\lambda' = 4.13\cdot 10^{-12} m +\frac{6.63\cdot 10^{-34} Js)}{(9.11\cdot 10^{-31}kg)(3\cdot 10^8 m/s)}(1-cos 77.5^{\circ})=6.03\cdot 10^{-12} m

7 0
3 years ago
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