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lions [1.4K]
2 years ago
10

Can anyone help explain a math question

Mathematics
1 answer:
bulgar [2K]2 years ago
8 0
The surface area of a solid object is a measure of the total area that the surface of an object occupies.
r = radius
h = height
V = volume
L = lateral surface area
T = top surface area
B = base surface area
A = total surface area
π = pi = 3.14159
√ = square root
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the ratio of the number of girls on a basketball team to the number of boys on the team is 5:4.what fraction of the players on t
Kazeer [188]
Well 5 + 4 is 9, and so if the girls are 5 in the ratio, the fraction would be 5/9. I hope this helps!
4 0
3 years ago
Read 2 more answers
Find the height of a parallelogram with base 6.75m and an area of 218.72 square meters
oksian1 [2.3K]

Answer:

about 32.4 meters

Step-by-step explanation:

The area of a parallelogram is the equation A=Base times Height.

Put in the known values 6.75m and 218.72meters squared into the equation.

It becomes the total area 218.72 = 6.75(h)

To get h or height by itself, you have to divide both sides by 6.75. You will get the answer 32.402, or you can round it to 32.4 meters.

7 0
3 years ago
I am a 2 dimensional shape. my perimeter is also known as a circumference
Daniel [21]
A circle...... maybe???
3 0
2 years ago
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How old is a dog when they are 40 in human years?
Scorpion4ik [409]

Answer:

280 years old

Step-by-step explanation:

to determine a dog's age in dog or human years, you divide or multiply by 7

40x7=280 years

4 0
3 years ago
I need help for this, thanks
gulaghasi [49]

(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.

---------------------------------------------------------------------------------------

(b) The following functions are positive in quadrant III:

tangent, cotangent

The following functions are negative in quadrant III

cosine, sine, secant, cosecant

A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.

5 0
3 years ago
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