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3 years ago

What is the speed of a bobsled whose distance-time graph indicates that it traveled 117m in 25s

Physics

1 answer:

Scilla [17]3 years ago

3 0

Speed= distance/time
speed=117/25
speed=4.68m/sec

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Physics is killing me. Any help?

Anni [7]

Answer:

The simplified expression is 3.833 x 10⁷ g

Explanation:

Given expression;

3.88 x 10⁷ g - 4.701 x 10⁵ g

The expression above is simplified as follows;

= (3.88 x 100 x 10⁵ )g - ( 4.701 x 10⁵) g

= (388 x 10⁵ )g - ( 4.701 x 10⁵) g

= (388 - 4.701 ) x (10⁵ )g

= 383.299 x 10⁵ g

In standard form, the simplified expression can be expressed as;

= (3.83299 x 100 x 10⁵) g

= 3.83299 x 10⁷ g

= 3.833 x 10⁷ g

Therefore, the simplified expression is 3.833 x 10⁷ g

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3 years ago

When placed in water does a pencil bend towards the normal or away from the normal?

Anarel [89]

Answer:

ni sin theta i = nr sin theta r where theta i is the angle of incidence and theta r the angle of refraction

For nr greater than ni (air to water) theta r must be smaller and the image would be bent towards the normal

7 0

3 years ago

The tub of a washer goes into its spin-dry cy-cle, starting from rest and reaching an angularspeed of 3.1 rev/s in 10.7 s.At thi

neonofarm [45]

Answer:

35 revolutions

Explanation:

t = Time taken

$\omega_f$ = Final angular velocity

$\omega_i$ = Initial angular velocity

$\alpha$ = Angular acceleration

$\theta$ = Number of rotation

Equation of rotational motion

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{3-0}{10.7}\\\Rightarrow \alpha=0.28037\ rev/s^2$

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}\\\Rightarrow \theta=\frac{3.1^2-0^2}{2\times 0.28037}\\\Rightarrow \theta=17.13806\ rev$

Number of revolutions in the 10.7 seconds is 17.13806

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-3.1}{11.2}\\\Rightarrow a=-0.27678\ rev/s^2$

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}\\\Rightarrow \theta=\frac{0^2-3.1^2}{2\times -0.27678}\\\Rightarrow \theta=17.36035\ rev$