Answer:
1. Just because it is small doesn't mean it needs to be excluded. If that were the case I would've been out of my friend group a while ago
2. Look at it it's fricking beautiful (see attachment)
3. It is just a great planet I don't think there needs to be any reason given I meannn you agree?
4. There's no other reason needed it's fricking gorgeous and amazing it needs no other reason. It needs a freaking
opening announcement to announce the arrival of the gorgeouness.
The student’s suggestion who provides enough evidence to be able to determine the value of each resistor is student D.
<h3>What is current?</h3>
The current is the stream of charges which flow inside the conductors when connected across the end of voltage.
For the given set of parallel resistors, we need to find the resistance of each resistor.
From the Ohm's law, V =IR
R = V/I
Resistance value depends upon the voltage difference across the resistor and the current flowing through that resistance.
Thus, the student D gives enough evidence to find resistance of the circuit is
Learn more about current.
brainly.com/question/10677063
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Answer:
6.1 × 10^9 Nm-1
Explanation:
The electric field is given by
E= Kq/d^2
Where;
K= Coulombs constant = 9.0 × 10^9 C
q = magnitude of charge = 1.62×10−6 C
d = distance of separation = 1.53 mm = 1.55 × 10^-3 m
E= 9.0 × 10^9 × 1.62×10−6/(1.55 × 10^-3 )^2
E= 14.58 × 10^3/2.4 × 10^-6
E= 6.1 × 10^9 Nm-1
To solve this problem it is necessary to apply the concepts related to the Conservation of Energy, for which it is necessary that any decrease made through the potential energy, is equivalent to the gain given in the kinetic energy or vice versa.
Mathematically this can be expressed as
Since there is no final potential energy (the height is zero), and the initial potential energy is equivalent to the work done we have to
Therefore the non-conservative work was done on the boy is 1.4kJ
Answer:
D or A ( I think)
Explanation:
Cause you know how people say the smaller the chips the more the chips its kind of the same with amplitude.
( hope it helps if I am wrong I am sorry)
