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g100num [7]
3 years ago
15

A boat is travelling down stream in a river at 20 m/s south. A passenger on the boat walks toward the back of the boat at 10 m/s

north. Relative to the ground, at what velocity is the passenger moving?
A) 10 m/s north
B) 10 m/s south
C) 30 m/s north
D) 30 m/s south
Physics
1 answer:
artcher [175]3 years ago
8 0

The question is unclear regarding the boat's velocity. Is it 20 m/s south relative to the water, or relative to the earth? (It is a river, after all...)

There's also the possibility that the boat's velocity relative to the river is 0. Take the south direction to be negative and north to be positive, and denote by v_{A/B} the velocity of a body A relative to a body B. Under these conditions,

v_{B/E}=v_{B/W}+v_{W/E}\iff-20\,\dfrac{\mathrm m}{\mathrm s}=0+-20\,\dfrac{\mathrm m}{\mathrm s}

(B for boat, E for earth, W for water) so that the passenger's velocity relative to the earth is

v_{P/E}=v_{P/B}+v_{B/W}+v_{W/E}

(P for passenger)

v_{P/E}=10\,\dfrac{\mathrm m}{\mathrm s}+0-20\,\dfrac{\mathrm m}{\mathrm s}=-10\,\dfrac{\mathrm m}{\mathrm s}

or 10 m/s south.

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Answer:

The intensity level in the room is 63 dB

Explanation:

To calculate the intensity of sound in the room, we use the equation of definition of decibels

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To calculate the intensity we will use the initial data and remember the power of the emitted sound is constant, in addition that the sound propagates in three-dimensional form or on a spherical surface

      I = P/A    ⇒    P = I A

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   I / Io = {10}^{\beta /10}

   I = Io  {10}^{\beta /10}

   I = 1 10⁻¹² 10⁽¹⁰⁰/¹⁰⁾   = 1 10⁻¹² 10¹⁰

   I = 1.0 10⁻² W

With this we can calculate the intensity for a distance of 20 m

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We have already found the intensity at the point of interest, so we can calculate the intensity in decibels at this point with equation 1

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The intensity level in the room is 63 dB

5 0
4 years ago
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Tapping means the maximum use of the energy by the people.

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Adhesive.

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