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g100num [7]
3 years ago
15

A boat is travelling down stream in a river at 20 m/s south. A passenger on the boat walks toward the back of the boat at 10 m/s

north. Relative to the ground, at what velocity is the passenger moving?
A) 10 m/s north
B) 10 m/s south
C) 30 m/s north
D) 30 m/s south
Physics
1 answer:
artcher [175]3 years ago
8 0

The question is unclear regarding the boat's velocity. Is it 20 m/s south relative to the water, or relative to the earth? (It is a river, after all...)

There's also the possibility that the boat's velocity relative to the river is 0. Take the south direction to be negative and north to be positive, and denote by v_{A/B} the velocity of a body A relative to a body B. Under these conditions,

v_{B/E}=v_{B/W}+v_{W/E}\iff-20\,\dfrac{\mathrm m}{\mathrm s}=0+-20\,\dfrac{\mathrm m}{\mathrm s}

(B for boat, E for earth, W for water) so that the passenger's velocity relative to the earth is

v_{P/E}=v_{P/B}+v_{B/W}+v_{W/E}

(P for passenger)

v_{P/E}=10\,\dfrac{\mathrm m}{\mathrm s}+0-20\,\dfrac{\mathrm m}{\mathrm s}=-10\,\dfrac{\mathrm m}{\mathrm s}

or 10 m/s south.

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use the pendulum equation to calcuate the period of a 1.50 pendulum. Remeber that the vaule of "g" is 9.81 m/s² please help ​
kati45 [8]

Answer:

L = 3.51

Explanation:

Pendulum equation is T = 2pi\sqrt{L/9.81}

T = 1.5 and we are solving for L

1.5=2\pi \sqrt{L/9.81}

square both sides to get 2.25 = 2\pi ( L/9.81)

multiply both sides by 9.81 then divide by 2 and 3.14 as a substitue for pi. The answer should be about 3.51 in length

L = 3.51

If this helps, mark me brainliest pls

3 0
3 years ago
A polycondensation reaction takes place between 1.2 moles of a dicarboxylic acid, 0.4 moles of glycerol (a triol) and 0.6 moles
katrin2010 [14]

Answer:

A) i) using statistical theory of floxy

(Pa)c = 0.816

(Pb)c = 0.816

ii) using Carothers theory

( Pc ) = 0.917

B) To Obtain the measured value of critical extent of reaction ( 0.866) 1 mol of Glycerol  will react with 1 mol of dicarboxylic acid, but the same can not be applied to our obtained value because our stoichiometry is different

Explanation:

Given data :

Polycondensation reaction takes place between : 1.2 moles of dicarboxylic acid , 0.4 moles of glycerol and 0.6 moles of ethylene glycol

A) Calculate the critical extents of reaction for gelation

i) using statistical theory of floxy

(Pa)c = 0.816

(Pb)c = 0.816

ii) using Carothers theory

( Pc ) = 0.917

attached below is the detailed solution

B) To Obtain the measured value of critical extent of reaction ( 0.866) 1 mol of Glycerol  will react with 1 mol of dicarboxylic acid, but the same can not be applied to our obtained value because our stoichiometry is different

3 0
3 years ago
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sammy [17]
Does it give you options?
3 0
2 years ago
An atom of carbon has a radius of 67.0 pm and the average orbital speed of the electrons in it is about 1.3 x 10⁶ m/s.
adoni [48]

Answer :

The least possible uncertainty in an electron's velocity is, 4.32\times 10^{5}m/s

The percentage of the average speed is, 33 %

Explanation :

According to the Heisenberg's uncertainty principle,

\Delta x\times \Delta p=\frac{h}{4\pi} ...........(1)

where,

\Delta x = uncertainty in position

\Delta p = uncertainty in momentum

h = Planck's constant

And as we know that the momentum is the product of mass and velocity of an object.

p=m\times v

or,

\Delta p=m\times \Delta v      .......(2)

Equating 1 and 2, we get:

\Delta x\times m\times \Delta v=\frac{h}{4\pi}

\Delta v=\frac{h}{4\pi \Delta x\times m}

Given:

m = mass of electron = 9.11\times 10^{-31}kg

h = Planck's constant = 6.626\times 10^{-34}Js

radius of atom = 67.0pm=67.0\times 10^{-12}m     (1pm=10^{-12}m)

\Delta x = diameter of atom = 2\times 67.0\times 10^{-12}m=134.0\times 10^{-12}m

Now put all the given values in the above formula, we get:

\Delta v=\frac{6.626\times 10^{-34}Js}{4\times 3.14\times (134.0\times 10^{-12}m)\times (9.11\times 10^{-31}kg)}

\Delta v=4.32\times 10^{5}m/s

The minimum uncertainty in an electron's velocity is, 4.32\times 10^{5}m/s

Now we have to calculate the percentage of the average speed.

Percentage of average speed = \frac{\text{Uncertainty in speed}}{\text{Average speed}}\times 100

Uncertainty in speed = 4.32\times 10^{5}m/s

Average speed = 1.3\times 10^{6}m/s

Percentage of average speed = \frac{4.32\times 10^{5}m/s}{1.3\times 10^{6}m/s}\times 100

Percentage of average speed = 33.2 % ≈ 33 %

Thus, the percentage of the average speed is, 33 %

3 0
3 years ago
Why do objects closer to you move faster than the objects far away when driving in a car?
ella [17]
It is kind of an optical illusion it is called <span>optical flow.</span>
7 0
2 years ago
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