Ask question

Ask question

All categories

2 years ago

14

Two things that electrical force depends upon?

1 answer:

lidiya [134]2 years ago

4 0

Electric force depends on the charge and the strength of the electric field. The equation that relates the three:

F = Eq where q is the charge and E is the electric field strength.

You might be interested in

What do you call the procedure that helps you determine the volume of an irregularly shaped object, while using a graduated cyli

Lena [83]

Water displacement. You fill a graduated cylinder with an amount of water, place the object inside the graduated cylinder, and then measure the new water level. The change in volume of the water is the volume of the object, assuming the object was completely submerged.

8 0

2 years ago

A student moves a box across the floor by exerting 56.7 N of force and doing 195 J of

Paha777 [63]

Answer:

A. 3.4 m

Explanation:

Given the following data;

Force = 56.7N

Workdone = 195J

To find the distance

Workdone is given by the formula;

$Workdone = force * distance$

Making "distance" the subject of formula, we have;

$Distance = \frac {workdone}{force}$

Substituting into the equation, we have;

$Distance = \frac {195}{56.7}$

Distance = 3.4 meters.

8 0

2 years ago

Your heart has four valves. Normally, these valves open to let blood flow through your heart, and then shut to keep it from flow

stiv31 [10]

Answer:

It influences blood flow

7 0

3 years ago

Chameleons catch insects with their tongues, which they can rapidly extend to great lengths. In a typical strike, the chameleon’

Yuki888 [10]

Answer:

0.2 m

Explanation:

PHASE 1

First, we calculate the distance the tongue moved in the first 20 ms (0.02 secs). We use one of Newton's equations of linear motion:

$s = ut + \frac{1}{2}at^2$

where u = initial velocity = 0 m/s

a = acceleration = $250 m/s^2$

t = time = 0.02 s

Therefore:

$s = 0 + \frac{1}{2} * 250 * (0.02)^2\\\\\\s = 0.05 m$

PHASE 2

Then, for the next 30 ms (0.03 secs), we use the formula:

$distance = speed * time$

This speed is the same as the final velocity of the tongue after the first 20 ms.

This can be obtained by using the formula:

$v = u + at\\\\=> v = 0 + (250 * 0.02)\\\\\\v = 5 m/s$

Therefore:

distance = 5 * 0.03 = 0.15 m

Therefore, the total distance moved by the tongue in the 50 ms interval is:

0.05 + 0.15 = 0.2 m

8 0

2 years ago

Do the data for the first part of the experiment support or

mrs_skeptik [129]

Answer:

your the class suru and Sahiba and Sahiba are all guddu saifi and Mam aap Aman and Sahiba are not

7 0

2 years ago