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Bingel [31]
2 years ago
5

Two skateboarders start a race at the same time skateboarder A travels at a steady rate of 15 feet per second skateboarder B tra

vels at a steady rate of 22 feet per second after 4 minutes how much farther will skateboarder B have traveled?
Mathematics
1 answer:
Dmitriy789 [7]2 years ago
7 0

Answer:

Step-by-step explanation:

Relative speed can play a major role in creating distance between two bodies. If the relative speed between two bodies is 0, then both the bodies are moving in the same direction with a similar speed. Thus, After 4 minutes, 1680 feet farther will Skateboarder B have traveled.

Skateboarder A travels at a steady rate of 15 feet per second.

Skateboarder B travels at a steady rate of 22 feet per second.

We need to determine that after 4 minutes, how much farther will Skateboarder B have traveled.

The formula for finding the distance travelled by anybody is represented below

Time is given that is 4 minutes which means 240 seconds.

Thus,

Distance travelled by skateboarder A

Distance travelled by skateboarder B.

Therefore, the separation of the distance between both the skateboarders is 5280 - 3600 = 1680.

Thus, After 4 minutes, 1680 feet farther will Skateboarder B have traveled.

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Step-by-step explanation:

Remove the parenthesis for each one so everything's out in the open. Next, you group like terms. The numbers with variables on one side, and the other numbers on the other side. For example:

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2 years ago
can Consider the expresion 6348 how you use distruptive propert and the Gcf to find the equielovent expression? Explain how you
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Step-by-step explanation:

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3 years ago
Which of the following is a point-slope equation of a line that passes through
Mademuasel [1]

Answer:

The Answer is: y = -2/3x + 10/3

Step-by-step explanation:

Given points (-1, 4) and (8, -2) first find the slope:

m = (y - y1)/(x - x1)

m = (4 - (-2)) / (-1 - 8)

m = 4 + 2 / -9

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Use the point slope form and point (8, -2) and slove for y:

y - y1 = m(x - x1)

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= 2/3 + 10/3

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Hope this helps! Have an Awesome Day!! :-)

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