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Bingel [31]
3 years ago
5

Two skateboarders start a race at the same time skateboarder A travels at a steady rate of 15 feet per second skateboarder B tra

vels at a steady rate of 22 feet per second after 4 minutes how much farther will skateboarder B have traveled?
Mathematics
1 answer:
Dmitriy789 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

Relative speed can play a major role in creating distance between two bodies. If the relative speed between two bodies is 0, then both the bodies are moving in the same direction with a similar speed. Thus, After 4 minutes, 1680 feet farther will Skateboarder B have traveled.

Skateboarder A travels at a steady rate of 15 feet per second.

Skateboarder B travels at a steady rate of 22 feet per second.

We need to determine that after 4 minutes, how much farther will Skateboarder B have traveled.

The formula for finding the distance travelled by anybody is represented below

Time is given that is 4 minutes which means 240 seconds.

Thus,

Distance travelled by skateboarder A

Distance travelled by skateboarder B.

Therefore, the separation of the distance between both the skateboarders is 5280 - 3600 = 1680.

Thus, After 4 minutes, 1680 feet farther will Skateboarder B have traveled.

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3 years ago
At a movie theatre adult tickets cost $10 and child ticjets cost $6. Which equation can be used to find s, the number of dollars
timurjin [86]

Answer:

s = 10k + 30

Step-by-step explanation:

Cost of Adults ticket = $10 per adult

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4 0
3 years ago
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Kobotan [32]
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3 years ago
Read 2 more answers
Joaquin has a grade of 81 and 70 on her first two algebra test if she wants an average of 73 what possible score can she get on
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81 + 70 + x = 219
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151 + x = 219
subtract 151 from both sides

x = 68

Joaquin needs to score a 68 on her next test to maintain an average of 73.
4 0
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