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3 years ago

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Two skateboarders start a race at the same time skateboarder A travels at a steady rate of 15 feet per second skateboarder B tra

vels at a steady rate of 22 feet per second after 4 minutes how much farther will skateboarder B have traveled?

1 answer:

Dmitriy789 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

Relative speed can play a major role in creating distance between two bodies. If the relative speed between two bodies is 0, then both the bodies are moving in the same direction with a similar speed. Thus, After 4 minutes, 1680 feet farther will Skateboarder B have traveled.

Skateboarder A travels at a steady rate of 15 feet per second.

Skateboarder B travels at a steady rate of 22 feet per second.

We need to determine that after 4 minutes, how much farther will Skateboarder B have traveled.

The formula for finding the distance travelled by anybody is represented below

Time is given that is 4 minutes which means 240 seconds.

Thus,

Distance travelled by skateboarder A

Distance travelled by skateboarder B.

Therefore, the separation of the distance between both the skateboarders is 5280 - 3600 = 1680.

Thus, After 4 minutes, 1680 feet farther will Skateboarder B have traveled.

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3 years ago

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A research study uses 800 men under the age of 55. Suppose that 30% carry a marker on the male chromosome that indicates an incr

ss7ja [257]

Answer:

a) There is a 12.11% probability that exactly 1 man has the marker.

b) There is a 85.07% probability that more than 1 has the marker.

Step-by-step explanation:

There are only two possible outcomes: Either the men has the chromosome, or he hasn't. So we use the binomial probability distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

30% carry a marker on the male chromosome that indicates an increased risk for high blood pressure, so $\pi = 0.30$

(a) If 10 men are selected randomly and tested for the marker, what is the probability that exactly 1 man has the marker?

10 men, so $n = 10$

We want to find P(X = 1). So:

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{10,1}.(0.30)^{1}.(0.7)^{9} = 0.1211$

There is a 12.11% probability that exactly 1 man has the marker.

(b) If 10 men are selected randomly and tested for the marker, what is the probability that more than 1 has the marker?

That is $P(X > 1)$

We have that:

$P(X \leq 1) + P(X > 1) = 1$

$P(X > 1) = 1 - P(X \leq 1)$

We also have that:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{10,0}.(0.30)^{0}.(0.7)^{10} = 0.0282$

So

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0282 + 0.1211 = 0.1493$

Finally

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.1493 = 0.8507$

There is a 85.07% probability that more than 1 has the marker.

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3 years ago

A store pays $35 for a fish tank. The markup is 20%. What is the selling price

snow_lady [41]

The selling price is $42

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3 years ago

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A rectangle has a length of 12 and a width that is half the length. What is the area?

Basile [38]

Answer:

Area = length x width

width = 1/2 length = 12/2 = 6 = width

area = 6x 12 = 72

Hope that answers your question

don't hesitate to comment if you are confused about something

Step-by-step explanation:

3 0

3 years ago

In how many ways can a subcommittee of 6 students be chosen from a committee which consists of 10 senior members and 12 junior m

givi [52]

Answer:

The number of ways is 13860 ways

Step-by-step explanation:

Given

Senior Members = 10

Junior Members = 12

Required

Number of ways of selecting 6 students students

The question lay emphasis on the keyword selection; this implies combination

From the question, we understand that

<em>4 students are to be selected from senior members while 2 from junior members;</em>

The number of ways is calculated as thus;

<em>Ways = Ways of Selecting Senior Members * Ways of Selecting Junior Members</em>

<em /> $Ways = ^{10}C_4 * ^{12}C2$

$Ways = \frac{10!}{(10-4)!4!)} * \frac{12!}{(12-2)!2!)}$

$Ways = \frac{10!}{(6)!4!)} * \frac{12!}{(10)!2!)}$

$Ways = \frac{10 * 9 * 8 * 7 *6!}{(6! * 4*3*2*1)} * \frac{12*11*10!}{(10!*2*1)}$

$Ways = \frac{10 * 9 * 8 * 7}{4*3*2*1} * \frac{12*11}{2*1}$

$Ways = \frac{5040}{24} * \frac{132}{2}$

$Ways = 210 * 66$

$Ways = 13860$

<em>Hence, the number of ways is 13860 ways</em>

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3 years ago