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Pani-rosa [81]
3 years ago
5

Guys guys GUYS guys guYs HELPhelp helppp

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
3 0

Answer:

A is 3 x 3 = 9 so thats one multiple and the ones that have the same put in the middle

Step-by-step explanation:

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Write the number which is a third of the way from -2 to -7?
artcher [175]

Answer: -5

Step-by-step explanation: -3 , -4 , -5 is the third

5 0
3 years ago
Please help<br> Find f(-3).<br><br> f(x) = 4x + 7<br> A) -5 <br> B) 5 <br> C) 6 <br> D) 10
irina1246 [14]

Answer:

A

Step-by-step explanation:

To evaluate f(- 3) substitute x = - 3 into f(x), that is

f(- 3) = 4(- 3) + 7 = - 12 + 7 = - 5 → A

7 0
3 years ago
17. Find x. Round to the nearest tenth if necessary. Assume that segments that appear to be
AlexFokin [52]

Answer:

x=19

Step-by-step explanation:

9*(9+15)=8*(8+x)

9*(24)=8(x+8)

216=8x+64

216-64=8x+64-64

152=8x

152/8=8x/8

19=x

x=19

8 0
2 years ago
Lottie buys a pack of 50 cans of lemonade.
malfutka [58]

Answer:

£15.7

Step-by-step explanation:

32 cans x 50P = 1600p

1600p to Pounds = £26.66 (1600 divided by 60)

Remaining cans = 18 (50 - 32)

18 cans x 20p = 360p

360p to Pounds = £6 (360 divided by 60)

£26.66 + £6 = £32.66

£32.66 (Profit) - £17 (Cost of cans) = £15.66

15.66 to 3SF = 15.7

3 0
2 years ago
Read 2 more answers
Find the volume of the solid under the plane 5x + 9y − z = 0 and above the region bounded by y = x and y = x4.
svp [43]
<span>For the plane, we have z = 5x + 9y

For the region, we first find its boundary curves' points of intersection.
x = x^4 ==> x = 0, 1.

Since x > x^4 for y in [0, 1],

The volume of the solid equals

\int\limits^1_0 { \int\limits_{x^4}^x {(5x+9y)} \, dy } \, dx = \int\limits^1_0 {\left[5xy+ \frac{9}{2} y^2\right]_{x^4}^{x}} \, dx  \\  \\ =\int\limits^1_0 {\left[\left(5x(x)+ \frac{9}{2} (x)^2\right)-\left(5x(x^4)+ \frac{9}{2} (x^4)^2\right)\right]} \, dx  \\  \\ =\int\limits^1_0 {\left(5x^2+ \frac{9}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx =\int\limits^1_0 {\left( \frac{19}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx \\  \\ =\left[ \frac{19}{6} x^3- \frac{5}{6} x^6- \frac{1}{2} x^9\right]^1_0

=\frac{19}{6} - \frac{5}{6} - \frac{1}{2} =\bold{ \frac{11}{6} \ cubic \ units}</span>
8 0
3 years ago
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