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3 years ago

2=2m−7 SOLVE FOR M PLS AND THANK YOU

Mathematics

2 answers:

Gala2k [10]3 years ago

7 0

Answer:

m = 4.5

Step-by-step explanation:

2 = 2m - 7

add 7 to both sides

9 = 2m

divide by 2 on each side

4.5 = m

CHECK:

2 = 2(4.5) -7 (TRUE)

2 · 4.5 = 9

9 - 7 = 2

I hope this helps!

PolarNik [594]3 years ago

7 0

Answer:

m=4.5

Step-by-step explanation: First, add 7 to each side and you get 9=2m. divide each side by 2 and you get m=4.5

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Part A:

a. The slope of AB is $-\frac{4}{5}$

b. The slope of CD is $-\frac{4}{5}$

Part B:

a. The slope of A'B' is $-\frac{4}{5}$

b. The slope of C'D' is $-\frac{4}{5}$

Step-by-step explanation:

- The rule of a slope of a line whose endpoints are $(x_{1},y_{1})$

and $(x_{2},y_{2})$ is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Part A:

∵ Point A = (3 , -3) and point B = (-2 , 1)

∵ Point C = (6 , 0) and point D = (1 , 4)

∴ $m_{AB}=\frac{1-(-3)}{(-2)-3}=\frac{1+3}{-2-3}=\frac{4}{-5}$

∴ The slope of AB is $-\frac{4}{5}$

∴ $m_{CD}=\frac{4-0}{1-6}=\frac{4}{-5}$

∴ The slope of CD is $-\frac{4}{5}$

- The image of point (x , y) by translation to the left k units is (x - k , y)

- Translation doesn't change the slope of a line, so the line and its

image have same slope

Part B:

∵ Segments AB and CD are translated 2 units to the left to get

segments A′B′ and C′D′

∵ Point A' = (3 - 2 , -3) and point B' = (-2 - 2 , 1)

∴ Point A' = (1 , -3) and point B' = (-4 , 1)

∵ Point C' = (6 - 2 , 0) and point D' = (1 - 2 , 4)

∴ Point C' = (4 , 0) and point D' = (-1 , 4)

∴ $m_{A'B'}=\frac{1-(-3)}{(-4)-1}=\frac{1+3}{-4-1}=\frac{4}{-5}$

∴ The slope of A'B' is $-\frac{4}{5}$

∴ $m_{C'D'}=\frac{4-0}{-1-4}=\frac{4}{-5}$

∴ The slope of C'D' is $-\frac{4}{5}$

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2=2m​−7 SOLVE FOR M PLS AND THANK YOU

2=2m−7 SOLVE FOR M PLS AND THANK YOU