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Mamont248 [21]
3 years ago
5

Please Answer ASAP !

Chemistry
1 answer:
amid [387]3 years ago
5 0

Answer:

2.0x 10-2M

Explanation:

x2/[2.0x10-2]2 [1.0x10-2] =100

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If 250.0 g of water at 30.0 °C cool to 5.0 °C, how many kilojoules of energy did the water lose?
Y_Kistochka [10]

Answer:

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Explanation:

Given data:

Mass of water = 250.0 g

Initial temperature = 30.0°C

Final temperature = 5.0°C

Amount of energy lost = ?

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Formula:

Q = m.c. ΔT

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ΔT = 5.0°C - 30.0°C

ΔT = -25°C

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Now we will put the values in formula.

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