Question

One of the few xenon compounds that form is cesium xenon heptafluoride (CsXeF7). How many moles of CsXeF7 can be produced from the reaction of 14.0 mol cesium fluoride with 14.0 mol xenon hexafluoride?
CsF(s) + XeF6(s) CsXeF7(s)

Answer 1

Answer : The number of moles of $CsXeF_7$ produced from the reaction is, 14 moles

Explanation :

The given balanced reaction is,

$CsF(s)+XeF_6(s)\rightarrow CsXeF_7(s)$

By the stoichiometry, 1 mole of cesium fluoride react with the 1 mole of xenon hexafluoride to give 1 mole of cesium xenon heptafluoride.

That means the mole ratio of $CsF:XeF_6:CsXeF_7=1:1:1$

As 14 moles of cesium fluoride react with the 14 moles of xenon hexafluoride to give 14 moles of cesium xenon heptafluoride.

Hence, the number of moles of $CsXeF_7$ produced from the reaction is, 14 moles