<span>The value of y when x=3 when the value of y varies directly with x^2, and y = 150 when x = 5 is 54. Since the value of y varies directly with x2, then: y = k * x^2, where k is constant. When y = 150 and x = 5, the value of constant is: 150 = k * 5^2. 150 = k * 25. k = 150/25. k = 6. Thus, when x = 3, the value of y will be: y = 6 * 3^2. y = 6 * 9. y = 54.</span>
Answer:
45q + 35
Step-by-step explanation:
Answer:
Step-by-step explanation:
(-4,-8)...x = -4 and y = -8
slope = 3/2
in y = mx + b form, the m is ur slope
now sub ur info into y = mx + b......we need to find b, the y intercept
y = mx + b
-8 = 3/2(-4) + b
-8 = -6 + b
-8 + 6 = b
-2 = b
so ur equation is : y = 3/2x - 2.....but u need it in another form
y = 3/2x - 2.....subtract 3/2x from both sides
-3/2x + y = -2 ....then u can multiply by -2 and get 3x - 2y = 4....just in case u dont want fractions
polynomial which has no real root is
