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2 years ago

Find the range and domain with vertex of 0, 4

Mathematics

2 answers:

BabaBlast [244]2 years ago

6 0

Answer:

Answer is below

Step-by-step explanation:

The domain of the quadratic equation is going to be all reals, since you can set x to be any real number and get a real value of y.

I can't see the graph, but the range of the quadratic is going to be y ≥ 4 (if the graph opens upwards) or y ≤ 4 (if the graph opens downwards).

If correct please give brainliest

Stay Safe and Healthy

Thank You

Lubov Fominskaja [6]2 years ago

4 0

Answer:

I'm the Akash Shukla I'm the Akash Shukla

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Lori creates the following design for a T-shirt.

kakasveta [241]

Solution-

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7

Area of rectangle 1 = 8.68 sq.in

$\Rightarrow FH \times HI=8.68$

$\Rightarrow EB \times HI=8.68$ (∵ sides of the rectangle 2)

$\Rightarrow 2.8 \times HI=8.68$

$\Rightarrow HI=3.1$

Area of Triangle 1 = 6.48 sq.in

$\Rightarrow \frac{1}{2}\times AE \times EG= 6.48$

$\Rightarrow \frac{1}{2}\times AE \times (EF+FG)= 6.48$

$\Rightarrow \frac{1}{2}\times AE \times (EF+HI)= 6.48$ (∵ sides of the rectangle 1)

$\Rightarrow EF+3.1= 5.4$

$\Rightarrow EF=2.3$

$\Rightarrow BH=2.3$ (∵ sides of the rectangle 2)

$BC = BH+HI+IC$

$\Rightarrow 11.7= 2.3+3.1+IC$

$\Rightarrow IC=6.3$

The area of Rectangle 2,

$=EB\times BH =2.8\times 2.3=6.44\ sq.in$

The area of Triangle 2,

$\frac{1}{2}\times GI \times IC=\frac{1}{2}\times EB \times IC=\frac{1}{2}\times 2.8 \times 6.3=8.82\ sq.in$

The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

= 6.48+8.68+8.82+6.44=30.42 sq.in

6 0

3 years ago

1. A quadrilateral is any four-sided polygon. Which of the following figures is a quadrilateral?

Yuliya22 [10]

Square, parallelogram, or rectangle. Any 4 sided object, just count the sides.

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3 years ago

please help! at a recent cross country meet, spectators had to pay to get in. it cost $7 for adults and $3 for students. the boo

erma4kov [3.2K]

Answer:

Step-by-step explanation:

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3 years ago

Simplify 9 (-2)�� 1 3 17

kaheart [24]

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3 years ago

Two lines in a coordinate plane have no points of intersection. Which pair could be the equations of the lines? A. 3x-2y=6, 6x-4

dem82 [27]

Answer:

Step-by-step explanation:

if to re-write all the equations:

A. y=3/2 x-3; y=3/2 x-3; B. y=-7x+10; y=3/2 x+3/2; C. y=x+5; y=-3/4 x+2; D. y=x+1; y= -3/4 x+8.

According to the re-written view the correct answer is 'A'.

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3 years ago