Hey JayDilla, I get 1/3. Here's how:
Kinetic energy due to linear motion is:
where
giving
The rotational part requires the moment of inertia of a solid cylinder
Then the rotational kinetic energy is
Adding the two types of energy and factoring out common terms gives
Here the "1" in the parenthesis is due to linear motion and the "1/2" is due to the rotational part. Since this gives a total of 3/2 altogether, and the rotational part is due to a third of this (1/2), I say it's 1/3.
It confirmed medeleeve's hypothesis (prediction) and showed the use of his table
Answer:
here
Explanation:
There are two forces acting upon the skydiver - gravity (down) and air resistance (up). The force of gravity has a magnitude of m•g = (72 kg) •(9.8 m/s/s) = 706 N. ... a 3.25-kg object rightward with a constant acceleration of 1.20 m/s/s if the force of ... of 33.8 kg, how far (in meters) will it move in 1.31 seconds, starting from rest?
Complete Question
A gas gun uses high pressure gas tp accelerate projectile through the gun barrel.
If the acceleration of the projective is : a = c/s m/s2
Where c is a constant that depends on the initial gas pressure behind the projectile. The initial position of the projectile is s= 1.5m and the projectile is initially at rest. The projectile accelerates until it reaches the end of the barrel at s=3m. What is the value of the constant c such that the projectile leaves the barrel with velocity of 200m/s?
Answer:
The value of the constant is
Explanation:
From the question we are told that
The acceleration is
The initial position of the projectile is s= 1.5m
The final position of the projectile is
The velocity is
Generally
and acceleration is
so
=>
integrating both sides
Now for the limit
a = 200 m/s
b = 0 m/s
c = s= 3 m
d == 1.5 m
So we have
=>