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3 years ago

A reaction that releases heat is what

Physics

1 answer:

pshichka [43]3 years ago

3 0

The reaction that releases heat is exothermic
exo- out of / outside
thermic - heat

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By counting the number of crests that pass in a given amount of time, a person can calculate the

ladessa [460]

By calculating the crests, you can find the waves' frequency.
Hope this helps!

3 0

3 years ago

How much heat is needed to boil 120 kg of water ?

nekit [7.7K]

Q = mc<span>∆t, where:
q = energy flow
m = mass, 120 000 g
c = specific heat capacity, 4.81 J/gC
</span><span>∆t = change in temperature, ~75 (100 - 25, which is room temperature)

Substituting in the values, we get:
q = 120000 x 4.81 x 75 = 43290000 Joules = 43.29 MJ

Hope I helped!! xx

</span>

7 0

3 years ago

Explain how atomic mass and molecular mass are determined

GaryK [48]

Molecular mass may be calculated by taking the atomic mass of each element present and multiplying it by the number of atoms of that element in the molecular formula. Then, the number of atoms of each element is added together. This value may be reported as a decimal number or as 16.043 Da or 16.043 amu.

4 0

3 years ago

Two tiny, spherical water drops, with identical charges of −8.00 ✕ 10^(−17) C, have a center-to-center separation of 2.00 cm.

Damm [24]

Answer:

F=1.4384×10⁻¹⁹N

Explanation:

Given Data

Charge q= -8.00×10⁻¹⁷C

Distance r=2.00 cm=0.02 m

To find

Electrostatic force

Solution

The electrostatic force between between them can be calculated from Coulombs law as

$F=\frac{kq^{2} }{r^{2} }$

Substitute the given values we get

$F=\frac{(8.99*10^{9} )*(-8.00*10^{-17} )^{2} }{(0.02)^{2} }\\ F=1.4384*10^{-19} N$

7 0

3 years ago

A piece of taffy slams into and sticks to another identical piece of taffy that is at rest. The momentum of the two pieces stuck

Yanka [14]

Answer:0.5

Explanation:

Given

Piece of taffy slams in to sticks to another identical piece and stuck into it.

Let m be the mass of taffy and u be the initial velocity of taffy and v be the final velocity of system.

Conserving momentum

$mu=2mv$

$v=\frac{u}{2}$

Initial kinetic energy $=\frac{mu^2}{2}$

Final Kinetic Energy $=\frac{2m(\frac{u}{2})^2}{2}=\frac{mu^2}{4}$

change in kinetic energy $\Delta K.E.=\frac{mu^2}{2}-\frac{mu^2}{4}=\frac{mu^2}{4}$

change in kinetic energy will contribute in heat energy

thus fraction of kinetic energy converted in to heat $=\frac{heat\ energy}{Initial\ kinetic\ Energy} =\frac{\frac{mu^2}{4}}{\frac{mu^2}{2}}=\frac{1}{2}=0.5$

5 0

4 years ago