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hammer [34]
3 years ago
15

4. A driver travels 135 km, east in 1.5 h, stops for 45 minutes for lunch,

Physics
1 answer:
stira [4]3 years ago
4 0

Answer:

The driver's average velocity is 82.35 km/h.

Explanation:

Given:

The motion of the driver can be divided into 3 parts:

i. Displacement of the driver in 1.5 hours = 135 km

ii. Rest for 45 minutes.

iii. Displacement in next 2 hours = 215 km

The direction of motion remains same (east).

Now, total displacement of the driver is, D_{Total}=135+215=350 km.

Rest time is 45 minutes. Converting it to hours, we need to use the conversion factor 1\textrm{ min} = \frac{1}{60} hour.

So, 45 minutes in hours is equal to \frac{45}{60}=0.75 hours.

Now, total time taken for the complete journey is, \Delta t=1.5+\frac{45}{60}+2=1.5+0.75+2=4.25\textrm{ h}

Average velocity is given as:

v_{avg}=\frac{\textrm{Total displacement}}{Total time}=\frac{350}{4.25}=82.35\textrm{ km/h}

Therefore, the driver's average velocity is 82.35 km/h

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<h2>3.94 kg</h2>

Explanation:

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Force ( f ) = 30 N

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force \:  = mass \:  \times acceleration

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Use the commutative property to reorder the terms

30 = 7.6 \: m

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\frac{7.6 \: m}{7.6}  =  \frac{30}{7.6}

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Option A.

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In quantum physics <u>there is a law to relate the position and the momentum of the particle</u>, it says that if we know with precision where is a quantum particle, we can not know the momentum of this particle, in other words, the velocity of the particle. So, when we measure the velocity of the particle we find the correct value of the particle, but we can not determine with accuracy where is the particle. This law is known as the Heisenberg's uncertainty principle and, its expressed as follows:    

\Delta x \Delta p \geq \frac{h}{4 \pi}

<em>where Δx: is the position's uncertainty, Δp: is the momentum's uncertainty and h: is the Planck constant.</em>  

Therefore, the correct answer is A: measuring the velocity of a tiny particle with an electromagnet has no effect on the velocity of the particle. It only affects the determination of the particle's position.      

I hope it helps you!

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A student walks 50 meters east, 40 meters north, 35 meters east, and then 20 m south. What is the magnitude and direction of the
Nuetrik [128]

Answer: A student walks 50 meters east, 40 meters north, 35 meters east, and then 20 m south. Then the magnitude and direction of the student's total displacement will be 87.32 m along the direction of AD or in east-south direction.

Explanation: To find the correct answer, we need to know about the Displacement of a body in motion.

<h3>What is displacement of a body in motion?</h3>
  • The displacement is the shortest distance between initial and final positions of a body.
  • It's a vector quantity, and can positive, negative, or zero.
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<h3>How to solve the problem?</h3>
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  • To solve this, we can use Pythagoras theorem.

AD=AC+CD\\AC^{2} =50^{2} +11^2\\AC=51.19 m\\Similarly,\\CD^2=35^2+9^2\\CD=36.13 m\\thus, \\AD=51.19+36.13=87.32 m

Thus, from the above calculations, we can conclude that, the displacement of the body will be equal to 87.32 m along the direction of AD or in east-south direction.

Learn more about the Displacement here:

brainly.com/question/28020108

#SPJ4

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