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Savatey [412]
4 years ago
7

Sound travels slow in cold air. Why does the speed of sound depend on air temperature?

Physics
1 answer:
Sergio [31]4 years ago
3 0
Heat is like sound, both are a form of kinetic energy. Molecules vibrate faster when at higher temps. since molecules vibrate faster, sound waves travel quicker  <span />
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A sample of oxygen gas at 25.0°c has its pressure tripled while its volume is halved. What is the final temperature of the gas?
Marat540 [252]

Answer:

447 K

Explanation:

25 C = 25 + 273 = 298 K

Assuming ideal gas, we can apply the ideal gas law

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

T_2 = T_1\frac{P_2}{P_1}\frac{V_2}{V_1}

Since pressure is tripled, then P_2 / P_1 = 3. Volume is halved, then V_2 / V_1 = 0.5

T_2 = 298*3*0.5 = 447 K

4 0
3 years ago
Read 2 more answers
NASA is giving serious consideration to the concept of solar sailing. A solar sailcraft uses a large, lowmass sail and the energ
Elan Coil [88]

Answer:

a) the reflective surface has twice the energy transfer

b) A = 1.3 10²⁷ km²

c) the energy emitted by the sun is distributed in a sphere that depends on the square of the distance, and the gravitational force depends on the square of the distance

Explanation:

a) The pressure exerted on the candle is related to the variation of the momentum

          P = \frac{1}{c} \ \frac{dp}{dt}

in a case of absorption (inelastic shock) all the energy is absorbed therefore the pressure is

          P = \frac{1}{c} \ \frac{dp}{dt}

in the case of reflection (elastic shock) an energy is absorbed by absorbing the light and then by action and reaction the same energy is absorbed in the reflected light

          P = 2  \frac{1}{c} \ \frac{dp}{dt}

In conclusion, the reflective surface has twice the energy transfer.

             

b) pressure is defined with force per unit area

           P = F / A

           F = P A

this force must be greater than the gravitational force of attraction of the sun

           Fg = G m Ms / r²

let's look for the case that the two forces are equal

           F = Fg

           P A_sail = G m Ms = r²

suppose a fully reflective sail

           2 \frac{S}{c}  \ A_{sail} = G \frac{m M_s}{r^2}

           

The pointing vector is the power delivered per unit area

           S = I = P / A

where A is the area of ​​the sphere where the is distributed by the sun

            A = 4π r²

we substitute

            \frac{2P}{c} \ \frac{A_{sail}}{4 \pi   r^2} = G \frac{m M_s}{r^2}

            \frac{1}{2 \pi \ c } A_{sail} = G m M_s

            A = G  m M_s 2π c

let's calculate

            A = 6.67 10⁻¹¹  10000 2 10³⁰ 2π  3 10⁸

            A = 1,257 10³³ m²

let's reduce to km²

            A = 1.3 10³³ m² (1km / 10³ m) ²

            A = 1.3 10²⁷ km²

c) The size of the candle is independent of the distance to the sun because the energy emitted by the sun is distributed in a sphere that depends on the square of the distance, and the gravitational force depends on the square of the distance, therefore the two dependencies are canceled.

8 0
3 years ago
Light in vacuum is incident on the surface of a glass slab. In the vacuum the beam makes an angle of 38.0° with the normal to th
iren [92.7K]

Answer:

n_glass = 1.404

Explanation:

In order to calculate the index of refraction of the light you use the Snell's law, which is given by the following formula:

n_1sin\theta_1=n_2sin\theta_2         (1)

n1: index of refraction of vacuum = 1.00

θ1: angle of the incident light respect to normal of the surface = 38.0°

n2: index of refraction of glass = ?

θ2: angle of the refracted light in the glass respect to normal = 26.0°

You solve the equation (1) for n2 and replace the values of all parameters:

n_2=n_1\frac{sin\theta_1}{sin\theta_2}=(1.00)\frac{sin(38.0\°)}{sin(26.0\°)}\\\\n_2=1.404

The index of refraction of the glass is 1.404

3 0
3 years ago
What is strength of the electric field between two parallel conducting plates separated by 1.00 cm and having an electric potent
Alex17521 [72]

Answer:

Electric field will be 1.5\times 10^{6}V/m

Explanation:

We have given potential difference between the two plates = 15000 volt

Distance between the plates = d=1cm=10^{-2}m

We have to find the electric field strength between the plates

Potential difference between the plates is equal to V=Ed

So electric field strength will be E=\frac{V}{d}=\frac{15000}{10^{-2}}=1.5\times 10^{6}V/m

So electric field will be 1.5\times 10^{6}V/m

6 0
3 years ago
What could be the average human density? Justify?
son4ous [18]

Answer:

985 kg/m3

Explanation:

The average density of the human body is 985 kg/m3 k g / m 3 , and the typical density of seawater is about 1020 kg/m3 k g / m 3 .

5 0
3 years ago
Read 2 more answers
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