Answer:
the acceleration due to gravity g at the surface is proportional to the planet radius R (g ∝ R)
Explanation:
according to newton's law of universal gravitation ( we will neglect relativistic effects)
F= G*m*M/d² , G= constant , M= planet mass , m= mass of an object , d=distance between the object and the centre of mass of the planet
if we assume that the planet has a spherical shape, the object mass at the surface is at a distance d=R (radius) from the centre of mass and the planet volume is V=4/3πR³ ,
since M= ρ* V = ρ* 4/3πR³ , ρ= density
F = G*m*M/R² = G*m*ρ* 4/3πR³/R²= G*ρ* 4/3πR
from Newton's second law
F= m*g = G*ρ*m* 4/3πR
thus
g = G*ρ* 4/3π*R = (4/3π*G*ρ)*R
g ∝ R
What is the structure of a hydrocarbon that has $\mathrm{M}^{+}=120$ in its mass spectrum and has the following $1 \mathrm{H}$ NMR spectrum? 7.25 $\delta(5 \mathrm{H}, \text { broad singlet); } 2.90 \delta(1 \mathrm{H}, \text { septet, } J=7 \mathrm{Hz}) ; 1.22 \delta(6 \mathrm{H},\text { doublet, }$ $J=7 \mathrm{Hz})$
Angular momentum is the measure of the amount of rotation of the body. It is the product of the moment of inertia and the angular velocity. The moment of inertia has the equation I=mr^2, where m is the mass and r is the radius of the circle. In this case, the radius is 0.6 m. Then, I = 2kg * (0.6)^2 = 0.72 kg-m2/s2.
The angular velocity on the other hand is the product of linear velocity and the radius. The equation is ω = rv, where v is the linear velocity. Therefore, ω = 0.6*1.1 = 0.66 rad/s
Therefore, the angular momentum is
= 0.72 kg-m2/s2*0.66 rad/s
= 0.48 kg-m^2/s
Hey!
Transmission light is the passage of light through a medium. Hence, the right answer must be option A.
Hope this helps :)
