A sample of oxygen gas at 25.0°c has its pressure tripled while its volume is halved. What is the final temperature of the gas?
2 answers:
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Answer:
discharge rate (Q) = 0.2005 m^{3} / s
Explanation:
if you read the question you would see that some requirements are missing, by using search engines, you can get the complete question as stated below:
Water flows steadily from an open tank as shown in the figure. (Figure 1) The elevation of point 1 is 10.0m , and the elevation of points 2 and 3 is 2.00 m . The cross-sectional area at point 2 is 4.80x10-2m ; at point 3, where the water is discharged, it is 1.60x10-2m. The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe. Part A Assuming that Bernoulli's equation applies, compute the volume of water DeltaV that flows across the exit of the pipe in 1.00 s . In other words, find the discharge rate \Delta V/Delta t. Express your answer numerically in cubic meters per second.
solution:
time = 1 s
elevation of point 1 (z1) = 10 m
elevation of point 2 (z2) = 2 m
elevation of point 3 (z3) = 2 m
cross section area of point 2 = 4.8 x 10^{2} m
cross section area of point 3 = 1.6 x 10^{2} m
g
acceleration due to gravity (g) = 9.8 m/s^{2}
find the discharge rate at point 3 which is the exit pipe.
discharge rate (Q) = A3 x V3
where A3 is the cross sectional area at point 3 and V3 is the velocity of the fluid and can be gotten by applying Bernoulli's equation below
pressure at point 1 (P1) is the same as pressure at point 3 (P3), and at point 1, the velocity (V1) = 0. therefore the equation now becomes
V3 =
V3 =
V3 = 12.53 m/s
discharge rate (Q) = A3 x V3 = 1.6 x 10^{-2} x 12.53
discharge rate (Q) = 0.2005 m^{3} / s
Answer:
a) The magnitude of the electric charge that a 60-kg human must have to overcome weight is 3.923 coulombs and its sign is negative.
b) The force of repulsion between two people is newtons. The use of the earth's electric field a feasible means of flight is not feasible since electric force of repulsion would destroy human body before taking advantage of any possible flight skill.
Explanation:
a) From Second Newton's Law, we form this equation of equilibrium:
(Eq. 1)
Where:
- Electrostatic force exerted on human, measured in Newton.
- Weight of the human, measured in Newton.
If we consider that human can be represented as a particle and make use of definitions of electric field and weight, the previous equation is expanded and electric charge is cleared afterwards:
(Eq. 2)
- Electric field, measured in Newtons per Coloumb.
- Mass, measured in kilograms.
- Gravity acceleration, measured in meters per square second.
- Electric charge, measured in Coulomb.
As electric field of the Earth is directed in toward the center of the planet, that is, in the same direction of gravity, electric field must be a negative value. If we know that ,
and
, the charge that a 60-kg human must have to overcome weight is:
The magnitude of the electric charge that a 60-kg human must have to overcome weight is 3.923 coulombs and its sign is negative.
b) The electric force of repulsion between two people with the same charge calculated in part (a) is determined by Coulomb's Law, whose definition we proceed to use:
(Eq. 3)
Where:
- Electrostatic constant, measured in Newton-square meter per square Coulomb.
- Electric charge, measured in Coulomb.
- Distance between two people, measured in meters.
If we know that ,
and
, then the force of repulsion between two people is:
The force of repulsion between two people is newtons. The use of the earth's electric field a feasible means of flight is not feasible since electric force of repulsion would destroy human body before taking advantage of any possible flight skill.