Not sure what im doing wrong on this, I've been using the equation
%2Bv_%7Bi%7Dt%20%2B%5Cfrac%7Bat%5E%7B2%7D%20%7D%7B2%7D" id="TexFormula1" title="y_{f} =y_{i} +v_{i}t +\frac{at^{2} }{2}" alt="y_{f} =y_{i} +v_{i}t +\frac{at^{2} }{2}" align="absmiddle" class="latex-formula"> and then using the quadratic formula to find the time, but i keep on getting 5.06s even though the answer is 3.64s, could someone tell me what I'm doing wrong please and show how to do it correctly? thanks in advance
1 answer:
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Answer:
Explanation:
The capacitor of a parallel-plate capacitor is given by:
where
A is the area of each plate
d is the separation between the plates
is the vacuum permittivity
The energy stored in a capacitor instead is given by
where
Q is the charge stored in each plate
Substituting the expression we found for C inside the last formula,
And re-arranging it
Now if we substitute
We find the charge stored on the capacitor:
Answer:
The total electric potential at mid way due to 'q' is
The net Electric field at midway due to 'q' is 0.
Solution:
According to the question, the separation between two parallel plates, plate A and plate B (say) = d
The electric potential at a distance d due to 'Q' is:
Now, for the Electric potential for the two plates A and B at midway between the plates due to 'q':
For plate A,
Similar is the case with plate B:
Since the electric potential is a scalar quantity, the net or total potential is given as the sum of the potential for the two plates:
Now,
The Electric field due to charge Q at a distance is given by:
Now, if the charge q is mid way between the field, then distance is .
Electric Field at plate A, at midway due to charge q:
Similarly, for plate B:
Both the fields for plate A and B are due to charge 'q' and as such will be equal in magnitude with direction of fields opposite to each other and hence cancels out making net Electric field zero.