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2 years ago

2. List the like terms in each of the following: i) 6a , 13b2 , -2a , 2a2 , -b2 , bc

Mathematics

1 answer:

lana [24]2 years ago

3 0

13b2 &-b2
6a & -2a

i m not sure about the answer ...

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Write the sentence as an equation.

bearhunter [10]

The solution to a given word problem by writing it as an equation is k = 253/232

<h3>Expressing word problems in mathematical forms:</h3>

The process of expressing word problems in mathematical forms takes a logical and chronological approach while taking the variables and arithmetic operations given into consideration.

From the given information, to express the word problem in mathematical form, we have:

253 = 232 × k
253 = 232k

Making k the subject of the equation, we have:

k = 253/232

Learn more about expressing word problems here:

brainly.com/question/10556265

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2 years ago

10 – 2v = -5v – 50 what is V

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I think it’s v=-20 i showed you my work if that helps :)

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3 years ago

In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion

lys-0071 [83]

$\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$

$\displaystyle
(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\
n=5\\
k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10$

----------------------------------------------------

$\displaystyle
(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\
n=5\\
k=4\\\\
\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90$

<u>It's 90</u>

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