All categories

3 years ago

So I have an F in science, and everything is due today. Am I going to fail 9th grade because I didn't pass that class?

2 answers:

4 0

You wont fail youll still go to your sophomore year, only that theyll make you retake the class to make up for credits :) hope this helps this is from my personal experience

Elis [28]3 years ago

3 0

Answer:

i dk how ur school works, but you'll most likely have to take that science again to get the credits u need to graduate

Explanation:

You might be interested in

PLEAAAASSE HELP FINAL EXAM Magnesium has 2 valence electrons. Sulfur has six valence electrons. What is the correct formula for

AleksandrR [38]

Answer:

Explanation:

need 8 valence electrons

6 0

4 years ago

Baking soda fizzing in vinegar is an example of a

Degger [83]

The correct answer is the second option. Baking soda fizzing in vinegar is an example of a chemical change. This example is a chemical reaction which undergoes a chemical change since new substances are being formed the fizzing of the system represent that gas is being produced by the reaction.

4 0

3 years ago

What percentage of strontium-90 remains in a sample after three half-lives have passed? 12.5% 15% 25% 60%?

Lyrx [107]

12.5% of strontium-90 would remain in a sample after three half-lives have passed. Half-life automatically means 50% of the original amount would remain.

4 0

3 years ago

Read 2 more answers

Many double-displacement reactions are enzyme-catalyzed via the "ping pong" mechanism, so called because the reactants appear to

zhenek [66]

Answer:

D. It will decrease by a factor of 4

Explanation:

According to the question , the equation follows :

$A+B\rightarrow C+D$

Rate law : This states the rate of reaction is directly proportional to concentration of reactants with each reactant raised to some power which may or may not be equal to the stoichiometeric coefficient.

$Rate\ \alpha [A]^{a}[B]^{b}$

$r=[A]^{a}[B]^{b}$ .................(1)

STEP": First, find out the power "a" and "b"

a+b = 3 (because it is given that the reaction follow 3rd order-kinetics)

According to question, doubling the concentration of the first reactant causes the rate to increase by a factor of 2 means,

r' = 2r if [A'] = 2[A]

Here [B] is uneffected means [B']=[B]

hence new rate =

$r'=[A']^{a}[B']^{b}$

Put the value of [A'] , [B'] and r' in the above equation:

$2r=[2A]^{a}[B]^{b}$ ...........(2)

Divide equation (1) by (2) we , get

$\frac{2r}{r}=\frac{[2A]^{2}[B]^{b}}{[A]^{a}[B]^{b}}$

$2= 2(\frac{A}{A})^{a}\times (\frac{B}{B})^{b}$

Here A and A cancel each other

B and B cancel each other

We get,

$2= 2^{a}\times 1^{b}$

1^b = 1 ( power of 1 = 1)

$2= 2^{a}$

This is possible only when a = 1

We know that : a + b = 3

1 + b = 3

b =3 -1 = 2

b = 2

Hence the rate law becomes :

$r=[A]^{a}[B]^{b}$

$r=[A]^{1}[B]^{2}$ .............(3)

Look in the question now, it is asked to calculate the concentration of [B],if cut in half

Hence

[B']=1/2[B]

Insert the value of [B'] in equation (3)

$r'=[A]^{1}[B']^{2}$

$r'=[A]^{1}(\frac{1}{2}[B])^{2}$

$r'=\frac{1}{4}[A]^{1}[B]^{2}$ ............(a)

But

$r=[A]^{a}[B]^{b}$ ..............(b)

Compare equation (a) and (b) , we get

new rate r' =

r' = 1/4 r

7 0

3 years ago

What is the independent variable when testing to see how the viscosity of a liquid affects its flow rate

DedPeter [7]

Answer:

Viscosity

Explanation:

The viscosity of the liquid is the independent variable. The flow rate is the dependent variable in this hypothesis.

The statement given is called the hypothesis. It is a form of scientific guess into a phenomenon.

An independent variable is the cause.
A dependent variable is the effect produced.
In this hypothesis, the cause of the various flow rate of the liquid is the viscosity.
It is therefore the independent variable.
The flow rate is the dependent variable.

3 0

3 years ago