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2 years ago

So I have an F in science, and everything is due today. Am I going to fail 9th grade because I didn't pass that class?

2 answers:

4 0

You wont fail youll still go to your sophomore year, only that theyll make you retake the class to make up for credits :) hope this helps this is from my personal experience

Elis [28]2 years ago

3 0

Answer:

i dk how ur school works, but you'll most likely have to take that science again to get the credits u need to graduate

Explanation:

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How is the atomic mass of an element calculated?

zloy xaker [14]

Answer:

Mass number (A) is the number of nucleons (proton and neutron) present in a atom.

Explanation:

electrons don't cout since they are thousandth's of the mass of protons or neutrons

6 0

2 years ago

Which particle has a mass that is approximately equal to the mass of a proton

Leto [7]

The answer is neutron

6 0

2 years ago

For the reaction IO3–(aq) + 5 I–(aq) + 6 H+(aq) → 3 I2(aq) + 3 H2O(l) the rate of disappearance of I–(aq) at a particular time a

scoray [572]

Answer: The rate of appearance of $I_2(aq)$ is $1.44\times 10^{-3}mol/Ls$

Explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

$IO_3^-(aq)+5I^-(aq)+6H^+(aq)\rightarrow 3I_2(aq)+3H_2O(l)$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

$Rate=-\frac{1d[I^-]}{5dt}=+\frac{d[I_2]}{3dt}$

Given: $-\frac{d[I^-]}{dt}]$ = $2.4\times 10^{-3}mol/Ls$

$+\frac{d[I_2]}{dt}=-\frac{3d[I^-]}{5dt}=-\frac{3}{5}\times 2.4\times 10^{-3}mol/Ls=1.44\times 10^{-3}mol/Ls$

The rate of appearance of $I_2(aq)$ is $1.44\times 10^{-3}mol/Ls$

6 0

2 years ago

Given the equation 2mg(s) + o2(g) → 2mgo(s) + 72.3 kj, how much heat is involved in the production of 5.0 mol of mgo? question 2

Rudik [331]

The heat is involved in the production of 5.0 mol of MgO is 180 Kj

   calculation

2 Mg (s) +O2 → 2 MgO

From the equation above two moles of MgO is used therefore

72.3 is for 2 moles

that is 72.3 kj = 2moles
? = 5 moles

by cross multiplication

= 72.3 kj × 5/2 = 180 Kj

7 0

2 years ago

1Calculate the density of an object that has a mass of 84.7g and a volume of 59.3 cm3

Iteru [2.4K]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 84.7 g

volume = 59.3 cm³

We have

$density = \frac{84.7}{59.3} \\ = 1.428330...$

We have the final answer as

Hope this helps you

7 0

2 years ago