Answer:
Molar mass of NH3,
MM = 1*MM(N) + 3*MM(H)
= 1*14.01 + 3*1.008
= 17.034 g/mol
mass(NH3)= 25.0 g
use:
number of mol of NH3,
n = mass of NH3/molar mass of NH3
=(25 g)/(17.03 g/mol)
= 1.468 mol
Molar mass of O2 = 32 g/mol
mass(O2)= 35.8 g
use:
number of mol of O2,
n = mass of O2/molar mass of O2
=(35.8 g)/(32 g/mol)
= 1.119 mol
The balanced chemical equation is:
4 NH3 + 5 O2 ---> 4 NO + 6 H2O
4 mol of NH3 reacts with 5 mol of O2 for 1.468 mol of NH3, 1.835 mol of O2 is required
But we have 1.119 mol of O2
so, O2 is limiting reagent
we will use O2 in further calculation
Molar mass of NO,
MM = 1*MM(N) + 1*MM(O)
= 1*14.01 + 1*16.0
= 30.01 g/mol
According to balanced equation
mol of NO formed = (4/5)* moles of O2
= (4/5)*1.119 = 0.895 mol
use: mass of NO = number of mol * molar mass
= 0.895*30.01
= 26.86 g
Answer: 26.9 g
Answer:
I think option a. Is correct in the graph C is the gas.....while in graph D is the ideal gas
Explanation:
Answer:The product formed on reaction with hydroxide ion as nucleophile is 2R-hexane-2-ol.
The product formed on reaction with water would be a 50:50 mixture of
2S-hexane-2-ol. and 2R-hexane-2-ol.
Explanation:
2S-iodohexane on reactiong with hydroxide ion would undergo SN² substitution reaction that is substitution bimolecular. Hydroxide ion has a negative charge and hence it is a quite good nucleophile .
The rate of a SN² reaction depends on both the substrate and nucleophile . Here the substrate is a secondary carbon center having Iodine as a leaving group.SN² reaction takes place here as hydroxide ion is a good nucleophile and it can attack the secondary carbon center from the back side leading to the formation of 2R-hexane-2-ol.
In a SN² reaction since the the nucleophile attacks from the back-side so the product formation takes place with the inversion of configuration.
When the same substrate S-2-iodohexane undergoes a substitution reaction with water as a nucleophile then the reaction occurs through (SN¹) substitution nucleophilic unimolecular mechanism .
The rate of a SN¹ reaction depends only on the nature of substrate and is independent of the nature of nucleophile.
The SN¹ reaction is a 2 step reaction , in the first step leaving group leaves leading to the formation of a carbocation and once the carbocation is formed then any weaker nucleophile or even solvent molecules can attack leading the formation of products.
In this case a secondary carbocation would be generated in the first step and then water will attack this carbocation to form the product in the second step.
The product formed on using water as a nucleophile would be a racemic mixture of R and S isomers of hexane -2-ol in 50:50 ratio. The two products formed would be 2R-hexane-2-ol and 2S-hexane-2-ol.
Kindly refer the attachment for reaction mechanism and structure of products.
Answer:
Genes are segments of DNA that are located on the chromosomes of each cell.
Explanation:
Chromosomes are basically tightly bundled thingies containing genes, DNA, whatever. Phenotype and genotype have nothing to do with chromosomes, that's just how WE describe them.